yes
The way to solve an arithmagon is to take the 3 box numbers, add them up and divide by 2. That gives your "center" number. For each corner circle, take the opposite box and subtract from the center number.
As long as you are allowed to have fractions and/or negative numbers, I think this method always works. Do you have an example of an impossible arithmagon?
For example:
a -- 7 -- b
.\ ........ /
. 8 ..... 9
... \ .. /
..... c
Add up 7+8+9 = 24
Divide by 2 = 12
a = 12 - 9 = 3
b = 12 - 8 = 4
c = 12 - 7 = 5
28 and 15
All you have to do is find the area divide it by the base and then you get the height.
1, 3, 6, 10, 15 ,21 The nth term for the sequence (where you replace n with the term you want to find) is: (n(n+1))/2
Divide the known circumference by pi to find the diameter of the circle.
To find the circumference of a circle in rhombus you eat SH*t .
triangular numbers are created when all numbers are added for example: To find the 5 triangular number (1+2+3+4+5).
Well, a triangle isn't a circle, so you cant find the circumference of it.
The numbers 1, 3, 6, 10, 15, 21, 28, . . . are know as triangular numbers. Find the greatest triangular number less than 5000.
The numbers 1, 3, 6, 10, 15, 21, 28, . . . are know as triangular numbers. Find the greatest triangular number less than 5000.
No, because the list is infinite. However, you can find them for yourself since the nth triangular number is n(n+1)/2
Do you know how to find the area of a circle when you know the radius ? Good! Do that. Do you know how to find the area of a square when you know the length of the side ? Good! Do that. Now you have two numbers ... the area of the circle and the area of the square. The problem wants you to find the difference of these two numbers. Do you know how to use subtraction to find the difference of two numbers ? Good! Do that.
take all the numbers and add them up.
-1999
You look at the edge of the triangular prism and count the points
28 and 15
The triangular numbers between 1 and 200 are 3, 6, 10, 15, 21, 28, 36, 45, 55, 66, 78, 91, 105, 120, 136, 153, 171, and 190. They are quite simple to find--each triangular number is one more than the difference between the previous two triangular numbers. For example, the difference between 55 and 66 is 11, so the next higher triangular number will be 78, 12 more than 66.
The only square number that is also a triangular number is 1. This is because square numbers are of the form n^2, while triangular numbers are of the form (n*(n+1))/2. When setting these two equations equal to each other and solving for n, we find that n=1 is the only integer solution. Therefore, 1 is the only number that is both a square number and a triangular number.