No, the closest you can get is 40p using 2 x 20p coins.
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There are 47 ways.
21 ways
Oh, what a happy little question! You can make one pound using different combinations of coins. You can use 100 one-penny coins, or 50 two-penny coins, or 20 five-penny coins, or 10 ten-penny coins, or 5 twenty-penny coins, or 2 fifty-penny coins. Just mix and match those coins and let your creativity shine!
There are 47 ways using 5p, 10p, 20p and 50p.
There are 201 ways.
There are 47 ways.
21 ways
Oh, what a happy little question! You can make one pound using different combinations of coins. You can use 100 one-penny coins, or 50 two-penny coins, or 20 five-penny coins, or 10 ten-penny coins, or 5 twenty-penny coins, or 2 fifty-penny coins. Just mix and match those coins and let your creativity shine!
To find the number of ways to make 50p using the given coins, we can use a technique called dynamic programming. We can create an array of size 51 to store the number of ways to make each value from 0 to 50p. We initialize the first element as 1 (since there is one way to make 0p), and then iterate through each coin denomination, updating the array based on the current coin value. Finally, the value at index 50 of the array will give us the total number of ways to make 50p using the given coins.
There are 47 ways using 5p, 10p, 20p and 50p.
There are 201 ways.
In order to make 50p using only 2p coins, you would need 25 of them. This is because each 2p coin is worth 2 pence, so 25 coins would equal 50 pence. This calculation is based on the fact that 100 pence make up £1, so half of that amount would be 50 pence.
One 50p and two 2p coins equals 54p.
10 because 50p x 10 = 500 p = £5
Use 50p, 20p, 20p, 5p and two 2p coins.
To make a pound using only 50p, 20p, and 10p coins, we can set up a linear Diophantine equation: 50x + 20y + 10z = 100, where x, y, and z are the number of each type of coin used. We can then use techniques such as generating functions or modular arithmetic to solve this equation and find the number of ways to make a pound. The solution will involve finding the integer solutions to the equation within a certain range, as there are constraints on the number of each type of coin available.
Fifteen 50p coins.