Yes
Yes, you can make 11 using only four 2s by using the following mathematical expression: (2 + 2) x (2 + 2) = 4 x 4 = 16. Then, subtract (2/2) to get 16 - 1 = 15. Finally, take the square root of 15 to get √15 ≈ 3.87, which is close to 4. Therefore, using four 2s, you can approximate 11 by following these steps.
2+ (2-2)x2 = 2
no, with 5 yes, 2x2x2-2/2 actually it depends on whether you accept differentiation in this. if yes, i can make it. 2+2+2+((d/dx)2)! =6+(0)! =7
22/2 - 2
22 + 22 - 2 = 42
Yes, you can make 11 using only four 2s by using the following mathematical expression: (2 + 2) x (2 + 2) = 4 x 4 = 16. Then, subtract (2/2) to get 16 - 1 = 15. Finally, take the square root of 15 to get √15 ≈ 3.87, which is close to 4. Therefore, using four 2s, you can approximate 11 by following these steps.
You can make 10 using four 2s by applying arithmetic operations. One way to do this is: ( (2 + 2) \times (2 + 2) = 4 \times 4 = 16 ), which is incorrect. However, you can also achieve 10 by using the equation: ( 2 \times 2 + 2 + 2 = 10 ).
22x2x2 is 88
2+ (2-2)x2 = 2
no, with 5 yes, 2x2x2-2/2 actually it depends on whether you accept differentiation in this. if yes, i can make it. 2+2+2+((d/dx)2)! =6+(0)! =7
Four 2s make 8, so 25% is your answer
you dont.
Yes. It's 22 x 2 ÷ 2
22/2 - 2
(2+2+2)=6 divided by the 4th 2 = 3
22 + 22 - 2 = 42
(2 + 2)*2/2 = 4