Choose a digit from 1-9 Make numbers that add to 1000 using only the digit you chose You can only use your digit eight times?

Answer 1

The sum 9 + 99 + 999 + 9999 + 99 999 + ....

where the last number to be added consists of nine digits of 9 becomes:

(10 – 1) + (100 – 1) + (1000 – 1) + (10 000 – 1) + ...

where the last multiple of 10 has nine zeros.

There are nine pairs of brackets altogether.

Add the multiples of 10 first and then subtract 9:

The digit 1 appears 9 times in the final answer.

Answer 2

Oh, dude, easy peasy! So, like, if we pick the number 1, we can do 111 + 111 + 111 + 111 + 111 + 111 + 111 + 111 = 888. Then we just add 1 + 1 + 1 = 3 to get 888 + 3 = 891. Boom, we got 1000 using the number 1 eight times!

Answer 3

To create numbers that add up to 1000 using a single digit from 1-9 and using it exactly eight times, you would choose the digit 1. The numbers would be 111 + 111 + 111 + 111 + 111 + 111 + 111 + 111 = 888. To reach 1000, you can then add 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 = 8. Therefore, 888 + 8 = 1000.

Answer 4

Using exactly eight 9's : 999 + ( 99/9 ) - ( 9/ .9 ) [ 999 + 11 - 10 = 1000 ] or (999 + 9/9) x ( 99-9) [ (999 +1 ) x 1 ] --(obviously the five 9's are enough : 999 + 9/9 )