There is no simple answer: in fact the search for the answer led to the study of elliptical integrals.
C = 2*pi*a*{1 - [1/2]^2*e^2 + [(1*3)/(2*4)]^2*e^4/3 - [(1*3*5)/(2*4*6)]^2*e^6/5 + ... }
where
a is the semi-major axis,
b is the semi-minor axis, and
e is the eccentricity = sqrt{(a^2 - b^2)/a^2}.
The above infinite series converges very slowly.
An approximation, suggested by Ramanujan, is
C = pi*{3(a + b) - sqrt[(3a + b)*(a +3b)]} = pi*{3(a + b) - sqrt[10ab + 3(a^2 + b^2)]}
Its circumference.
It isn't possible to give a generalised formula for the circumference of an ellipse in terms of elementary functions. The circumference (or perimeter) of an oval is represented by an infinite series based on multiple aspects of the oval including: * Eccentricity * Implied length ("major radius") * Implied width ("minor radius")
The shape (circular, oval, rectangular, irregular, etc.) must be given as well as the area.
2 in regular and 1 in normal oval(egg)
part of track oval
If it is an elliptic oval, the circumference can be calculated by πab, where a and b are the lengths of the minor and major axes.
Its circumference.
You circumference anything that is round. (eg. A circle, and oval, etc.) -Hope this helps
It isn't possible to give a generalised formula for the circumference of an ellipse in terms of elementary functions. The circumference (or perimeter) of an oval is represented by an infinite series based on multiple aspects of the oval including: * Eccentricity * Implied length ("major radius") * Implied width ("minor radius")
To find the linear feet around an oval, you would typically calculate the circumference. The formula for the circumference of an oval is (a + b)π, where a and b are the semimajor and semiminor axes of the oval. In this case, for a 33x18 foot oval, the semimajor axis (a) would be 33/2 = 16.5 feet and the semiminor axis (b) would be 18/2 = 9 feet. Therefore, the circumference would be (16.5 + 9)π = 25.5π feet. This is approximately 80.07 feet.
Talledega, 2.66 miles in circumference
NO!!! Circle ; from its centre the distance to the edge(circumference) is equal . Ellipse(Oval) ;from its centre the distance to its edge(circumference) can vary. Casually, you can think of an oval as a squashed circle. In the coordianet plane ; A circle has the Equation x^2 + y^2 = 1 An Oval has the Equations x^2/a^2 + y^2/b^2 = 1 The 'a' & 'b' represent the eccentricity of the oval (ellipse), and the lengths of the major and minor axes.
The shape (circular, oval, rectangular, irregular, etc.) must be given as well as the area.
Oval = 2 semicircles connected with two parallel lines which are spaced by the diameter of the semicircle. Circumf. = (Pi x 15) + (2*15) = 15 Pi + 30 = 77.124 (to nearest 3rd decimal). Please note that an oval is not an ellipse.
If you use the formula for determining the circumference of a circle, C=pi*diameter, you can calculate the "ends" of the oval and then determine how long the sides of the oval need to be. For example, if the distance between the 2 long parallel sides of the oval is 20 yards, the circumference of a circle with the diameter of 20 yards is 63 yards (actually 62.8). If you dissect the circle and use one side for one end of the oval and the other side for the other end, you end can figure out how long the parallel sides would need to be. Calculate the length of the 2 sides, subtract 63 yards, the measurement of the 2 ends of the oval, from 220. This would be 157 yards. Then divide 157 by 2 to get the length of the 2 sides of the oval. This would be 78.5 yards. Therefore, the dimensions of this oval would be 20 yards wide by 98.5 yards.
they each run 107.5 meters.
No, it cannot. A chord of a circle is a line segmentwhich has its endpoints on the curve (or circumference) of the circle. A line segment is part of a line, and a line is straight. It's that simple.