The command line is represented in C or C++ as a call to main with two arguments...
int main (int argc, char* argv[]);
The argc variable is the number of arguments, and is always at least 1, because the first argument, argv[0], is the program name itself.
Each word in the command line is then presented in successive argv[n] variables. For instance, if you type thiscommand one two three, argc will be 4, and argv[n], n being 0 through 3, will be "thiscommand", "one", "two", and "three", without the quotation marks, of course.
Some implementations provide other functionality, such as an additional char *envp[] argument which contains the environment, but that is not ANSI. In the MS Windows environment, the entry point is to winmain for windows programs, and to main for console programs.
int WinMain(HINSTANCE hInstance, HINSTANCE hPrevInstance, LPTSTR lpCmdLine, int nCmdShow);
In this case, the full command line is in lpCmdLine.
Other operating systems may have alternate entry points, but I do not know them as well as MS Windows. Other contributors - please refine this answer if appropriate.
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Syntax error is a kind of error when compiler does not recognize the command you are trying to use. It happens because of two reasons: first is you forgot to include required library; second is such command does not exist.
If a line has equation y = mx + c, the perpendicular line has gradient -1/m A line perpendicular to 3x + y = 2 has equation 3y = x + c; the value for c will be determined by a point through which the line must pass.
b + b + b + c + c + c + c = 3b + 4c
c + c + c + c + c = 5 * c.
A linear equation ?