Although no incomplete ordered pairs have been shown they can be readily solved.
If x + y - 1 = 0, then x = 1 - y, also y = 1 - x.
From the above formulae for x and y then any omissions can be completed.
EXAMPLE : complete the ordered pairs (1) (7, y) and (2) (x, -4)
(1) y = 1 - x = 1 - 7 = -6 : The ordered pair is thus (7, -6)
(2) x = 1 - y = 1 -(-4) = 5 : The ordered pair is thus (5, -4)
The equation 2x-5y=-1 has a graph that is a line. Every point on that line is an ordered pair that is a solution to the equation. So pick any real number x and plug it in. You will find a y and that pair (x,y) is an ordered pair that is a solution to this equation. For example, let x=0 Then we have -5y=-1so y=1/5 The ordered pair (0, 1/5) is a point on the line and a solution to the equation.
y=(-1) x=(2)
Plug your ordered pair into both of your equations to see if you get they work.
Tell whether the ordered pair (5, -5) is a solution of the system
There are an infinite number of solutions to this equation, some of which are (9,0), (12,2), (15,4), (18,6), (21,8)
(0, 6)
There are an infinite number of ordered pairs. (-5, -7) is one pair
(4.25, 0.25) is a solution.
7
There are an infinite number of ordered pairs that satisfy the equation.
There are infinitely many ordered pairs: each point on the straight line defined by the equation is an ordered pair that is a solution. One example is (0.5, 2.5)
(10, 2)
(0, 6.5) is one option.
Substitute the values of the ordered pair into the relation. If the equation is valid then the ordered pair is a solution, and if not then it is not.
The equation 2x-5y=-1 has a graph that is a line. Every point on that line is an ordered pair that is a solution to the equation. So pick any real number x and plug it in. You will find a y and that pair (x,y) is an ordered pair that is a solution to this equation. For example, let x=0 Then we have -5y=-1so y=1/5 The ordered pair (0, 1/5) is a point on the line and a solution to the equation.
y=(-1) x=(2)
12