0
main()
{
int i,c=0,sum=0;
scanf("%d",&i);
while(i>=0)
{
i=i%2;
sum=sum+i*pow(10,c);
i=i/2;
c++
}
printf("%d",sum);
}
OR =)
#include<stdio.h>
#include<conio.h>
void showbits(int h)
{
if(h==1)
printf("%d",h);
else
{
showbits(h/2);
printf("%d",h%2);
}
}
void main()
{
int nu;
void showbits(int h);
clrscr();
printf("Num?");scanf("%d",&nu);
printf("\nBin eq of %d is ",nu);
showbits(nu);
getch();
}
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C plus plus program that convert decimal to binary using the concept of stack?
#include<stdio.h> #include<stdlib.h> main() { int number,binary[10000],b=0; printf("Enter decimal number "); scanf("%d",&number); printf("\nBinary: "); for(;number;number/=2,b++) binary[b]=number%2; for(b--;b>-1;b--) printf("%d ",binary[b]); }
How do you convert hexadecimal form to binary form?
Each hexadecimal digit (or nybble) is the equivalent of 4 binary digits (or bits) with a decimal value of 0-15. Convert each nybble into (4) binary (digits) and string them together, remembering the conversion of decimal 0-15 to binary: Hex -> Dec -> Binary 0 -> 00 -> 0000 1 -> 01 -> 0001 2 -> 02 -> 0010 3 -> 03 -> 0011 4 -> 04 -> 0100 5 -> 05 -> 0101 6 -> 06 -> 0110 7 -> 07 -> 0111 8 -> 08 -> 1000 9 -> 09 -> 1001 A -> 10 -> 1010 B -> 11 -> 1011 C -> 12 -> 1100 D -> 13 -> 1101 E -> 14 -> 1110 F -> 15 -> 1111 So to convert 0x6AF to binary: 6 -> 0110 A -> 1010 F -> 1111 => 0x6AF = 0110 1010 1111 = 011010101111 (without the spaces showing the hex nybbles)
Fibonacci sequence code in turbo-C?
turn off your pc.
Pseudocode for subtraction of two binary numbers?
start read a read b c=a-b print c end
How many decimal places would you move for a conversion from a cm to a mm?
k h da 1 . d c m kilo hecto deka meter, liter, gram, etc. (Base) . deci centi milli If you want to convert from centimeters to millimeters, move the decimal one decimal place to the right. King Henry Died By (Base) Drinking Chocolate Milk If you can remember the top or the acronym, you'll never have this problem again.
