Convert each group of 4 bits into one hexadecimal digit. 1010 is "A" in hexadecimal, so this particular number is "AA".
I assume the number is in binary. Separate the binary number from the right, 4 digits at a time: 1011 1011. Then convert each group of four binary digits to hexadecimal. In this case, 1011 is B, so the answer is 0xBB (the prefix 0x is often used to indicate hexadecimal).I assume the number is in binary. Separate the binary number from the right, 4 digits at a time: 1011 1011. Then convert each group of four binary digits to hexadecimal. In this case, 1011 is B, so the answer is 0xBB (the prefix 0x is often used to indicate hexadecimal).I assume the number is in binary. Separate the binary number from the right, 4 digits at a time: 1011 1011. Then convert each group of four binary digits to hexadecimal. In this case, 1011 is B, so the answer is 0xBB (the prefix 0x is often used to indicate hexadecimal).I assume the number is in binary. Separate the binary number from the right, 4 digits at a time: 1011 1011. Then convert each group of four binary digits to hexadecimal. In this case, 1011 is B, so the answer is 0xBB (the prefix 0x is often used to indicate hexadecimal).
101102 = 2210 = 1616 = 268
The answer depends on what you are converting from: binary, ternary, octal, hexadecimal ...
You could first convert it to binary, and then to hexadecimal. Because octal and hexadecimal bases are both powers of two, the conversion between those bases and binary is quite easy. To go from octal to binary, take each digit in the number, and convert it to three binary digits: 5 -> 101 3 -> 011 2 -> 010 4 -> 100 So the binary version of the number is: 101 011 011 010 100 In order to convert to hexadecimal, your number of digits needs to be divisible by four (as 24 = 16). To get that, we need to add a digit, which will be a zero as our leftmost digit: 0101 0110 1101 0100 Now we can convert each of those sets of four binary digits into single hexadecimal digits, giving us our final answer: 9AD8
Convert each group of 4 bits into one hexadecimal digit. 1010 is "A" in hexadecimal, so this particular number is "AA".
That depends what you want to "solve" for - in other words, what the question is. For example, whether you want to:* Convert from hexadecimal to decimal* Convert from decimal to hexadecimal* Count in hexadecimal* Add hexadecimal numbers* etc.
Assuming the original was in binary, the answer is 36.A
Hexadecimal -> BB895Cdecimal -> 12.290.396octal -> 56.704.534
Write a program to convert a 2-digit BCD number into hexadecimal
Whatchu think
117
Yes, I can.
WRITE A PROGRAM TO CONVERT A 2-DIGIT bcd NUMBER INTO HEXADECIMAL
747 = 1E7
7EBC.12
To store the hexadecimal number FF, we need to convert it to binary first. FF in hexadecimal is equivalent to 1111 1111 in binary, which requires 8 bits to represent. Each hexadecimal digit corresponds to 4 bits in binary, so two hexadecimal digits (FF) require 8 bits to store.