63
65
63
Find the greatest product of five consecutive digits in the 1000-digit number.7316717653133062491922511967442657474235534919493496983520312774506326239578318016984801869478851843858615607891129494954595017379583319528532088055111254069874715852386305071569329096329522744304355766896648950445244523161731856403098711121722383113622298934233803081353362766142828064444866452387493035890729629049156044077239071381051585930796086670172427121883998797908792274921901699720888093776657273330010533678812202354218097512545405947522435258490771167055601360483958644670632441572215539753697817977846174064955149290862569321978468622482839722413756570560574902614079729686524145351004748216637048440319989000889524345065854122758866688116427171479924442928230863465674813919123162824586178664583591245665294765456828489128831426076900422421902267105562632111110937054421750694165896040807198403850962455444362981230987879927244284909188845801561660979191338754992005240636899125607176060588611646710940507754100225698315520005593572972571636269561882670428252483600823257530420752963450
48
These are the first 31 digits of pi:3.1415926535897932384626433832795The number not found is zero
To compare numbers start with the left most place value column that contains a non-zero digit in at least one of the numbers and continue right until a different is found. If a number does not have a digit in a place value column where the other number(s) do(es), then the blank column can be considered as containing a zero. The first non-zero digit of 14.5 is in the tens column (2 before the decimal point) The first non-zero digit of 0.809 is in the tenths column (the first after the decimal point) → start at the tens column 14.5 has 1 in the tens column 0.809 has a blank tens column, so it is considered as a 0. 1>0 therefore 14.5 is greater than 0.809
Well, let's see. Perfect cubes that are two digits: 27 64 Could it be 27? Well, 2+7 is 9, and that's a perfect square with a square root of 3, and the cube root of 27 is three. Looks like we've found our answer, especially since 6+4 = 10, which is NOT a perfect square.
63
These are the first 31 digits of pi:3.1415926535897932384626433832795The number not found is zero.
If the number is odd, the last digit is odd. That means the ten's digit must be twice the one's digit. There are only four two-digit numbers where the ten's digit is twice the one's digit: 21, 42, 63, 84. Check which of these satisfy all the clues.
Find the greatest product of five consecutive digits in the 1000-digit number.7316717653133062491922511967442657474235534919493496983520312774506326239578318016984801869478851843858615607891129494954595017379583319528532088055111254069874715852386305071569329096329522744304355766896648950445244523161731856403098711121722383113622298934233803081353362766142828064444866452387493035890729629049156044077239071381051585930796086670172427121883998797908792274921901699720888093776657273330010533678812202354218097512545405947522435258490771167055601360483958644670632441572215539753697817977846174064955149290862569321978468622482839722413756570560574902614079729686524145351004748216637048440319989000889524345065854122758866688116427171479924442928230863465674813919123162824586178664583591245665294765456828489128831426076900422421902267105562632111110937054421750694165896040807198403850962455444362981230987879927244284909188845801561660979191338754992005240636899125607176060588611646710940507754100225698315520005593572972571636269561882670428252483600823257530420752963450
48
63
The first occurrence of the digit 0 in the digits of pi is at the 32nd decimal place.
4 options for the first digit, 3 options for the second digit, 2 options for the third digit. Multiply the number of options together, and you find how many 3-digit numbers you can get.
A four digit whole number can be found from 1000 to 9999
It has been proven that there is no largest prime number, and therefore there exists a prime number, in fact, infinitely many, greater than 10^999999999 (having a billion digits); however, no humans have actually found a specific number of that size and identified it as prime.
There are 9 pages that use a single digit (pages 1-9), leaving 495 digits - 9 pages × 1 digit/page = 486 digits There are 90 pages that use 2 digits (pages 10-99), leaving 486 digits - 90 pages × 2 digits/page = 306 digits There are 900 pages that use 3 digits (pages 100-999); this would be 2,700 digits, so the number of pages is somewhere in the hundreds. 306 digits ÷ 3 digits/page = 102 pages in the hundreds. → total number of pages = 102 + 90 + 9 = 201 pages.
there should be six answers