1100-1300 ft/sec
pi*65 which is just over 204 mm
The thirty-aught-six (30-06) bullet diameter is .308 in (7.62 mm) The "30" designates the projectile as 30 caliber, whilst the "06" indicates the year the round was adopted and standardized by the US Military.
27
Not at all. Remember, at one time the sizes of coins were proportional to their values so a Morgan dollar is (essentially) twice the size of a Kennedy half dollar. Specifically, Morgan dollars are 38 mm in diameter and weigh 26.7 gm when new. JFK halves are 30 mm in diameter and weigh anywhere from 11.34 gm to 12.5 gm depending on their metal composition.
65 mm is about 2.55905511811024 inches. Direct Conversion Formula 65 mm* 1 in 25.4 mm = 2.559055118 in
65 mm = 6.5 cm
It depends on the bullet weights. The 9 mm (AKA 9x19 mm, 9 mm Luger, or 9 mm Parabellum) is faster than the .380 ACP (AKA 9 mm Kurz) except when you compare the lightest .380 bullets to the heaviest 9 mm bullets. If you compare the same bullet weights in each, the 9 mm is always faster.
11.5 mm bullet diameter
65 cm = 650 mm
The M-16 round is a 5.56 mm round. It's smaller than an AK-47 round (7.62mm) A 5.56 mm will kill easily! Hoo-ah
1 cm = 10 mm → 65 cm = 65 × 10 mm = 650 mm
Millimeters, it is the size of the bullet.
25.4 mm = 1 in → 65 mm = 65 ÷ 25.4 in ≈ 2.56 in
0.0065 dam, algebraic steps below: 65 mm*1 dam 10000 mm=0.0065 dam
The answer depends on what the 65 mm refers to: the radius of the diameter. Please specify.
0.25591" Direct Conversion Formula 6.5 mm* 1 in 25.4 mm = 0.2559055118 in