It means that no one has to move for the distribution of two groups under study in a particular area to match the population distribution.
For example, if a county was 10% black and 90% white, you would get an index of dissimilarity of 0 if, in the smaller area under study (such as a Census block group), you found 10% of the smaller area was black and 90% was white.
If the Z Score of a test is equal to zero then the raw score of the test is equal to the mean. Z Score = (Raw Score - Mean Score) / Standard Deviation
Mean = 0 SD = 1 The whole point of converting to a Z-score is that you have a Standard Normal distribution ie a N(0, 1) distribution.
The z score for the mean is always 0.
1.41
score = 0; Put the code in a collision event.
Yes.z = (raw score - mean)/standard error.Since the standard error is positive, z < 0 => (raw score - mean) < 0 => raw score < mean.
A z-score of 0 means the value is the mean.
If the Z Score of a test is equal to zero then the raw score of the test is equal to the mean. Z Score = (Raw Score - Mean Score) / Standard Deviation
Z score of 0 is the mean of the distribution.
Mean = 0 SD = 1 The whole point of converting to a Z-score is that you have a Standard Normal distribution ie a N(0, 1) distribution.
Answer: 0 The z score is the value of the random variable associated with the standardized normal distribution (mean = 0, standard deviation =1). Now, the median and the mean of a normal distribution are the same. The 50 percentile z score = the median = mean = 0.
The z score for the mean is always 0.
yes. z score measures distance from 0. 0 represents the mean.
A Z-Score of 0 separates the upper 50% of the area from the lower 50% of the area. A Z-Score of 0 is at the mean, median, and mode of the distribution.
no score draw is = 0-0
The dimensional formula for relative refractive index is [M^0 L^0 T^0].
IQ is distributed normally, with a mean of 100 and a standard deviation of 15. The z-score of 100 is therefore:(value-mean)*standard deviation= (100-100)*15= 0More generally, a raw score that is equivalent to the mean of a normal distribution will always have a z-score of 0.