Divide 282 into two parts such that the eighth part of the first and the fifth part of the second are in the ratio 4 to 3?

Answer 1

Oh honey, math problems, my favorite! Let's break it down: Let the two parts be x and 282-x. According to the problem, (1/8)x = 4/3(1/5)(282-x). Now just solve that bad boy and you'll have your two parts! Math never looked so good, darling.

Answer 2

Let the two parts be x and 282-x. According to the given condition, (1/8)x : (1/5)(282-x) = 4 : 3. Simplifying this equation, we get x/8 : (282-x)/5 = 4/3. Cross multiplying and solving for x, we find x = 160.8. Therefore, the two parts are approximately 160.8 and 121.2.

Answer 3

if first part is considered as x, then second part is 282-x

eighth part of first =x/8

fifth part of second =(282-x)/5

given condition

x/8:(282-x)/5 = 4:3

x/8:(282-x)/5= 4/3

5x/8(282-x)= 4/3

15x = 32(282-x)

15x = 9024 - 32x

15x + 32x = 9024

47x = 9024

x = 9024/47 = 192

so, first part = 192

second part = 282 - x = 282 - 192 = 90

enjoy!

G.SUNAND

GRADE VIII