We know that the sum of the exterior angles of a regular polygon is 360°. Since the exterior angle is 24°, then 24°n = 360° divide both sides by 24°; n = 15 Thus a 15-sided regular polygon has an exterior angle of 24°. If you don't remember the above fact, you can work in this way: If the exterior angle is 24°, then the angle of polygon will be 156° (180 - 24). Since the sum of the angle of the polygon is equal to (n - 2)180°, then we have: 156° n = (n - 2)180° 156° n = 180°n - 360° subtract 156°n and add 360° to both sides; 360° = 24°n divide by 24° to both sides; 15 = n
Divide the angle sector by 360 and multiply it by 24 square meters. The area is equal to 3 square meters.
50
Yes; 384 = 360 + 24, divide each number by 6 to get 60 and 4, then add the numbers up to get 64.
Yes. 360 divided by 15 is 24.
its 360/15 = 24 degrees
Because it turns steadily and goes through 360 degrees in 24 hours, so you just have to divide 360 by 24.
Divide it into segments (like pizza slices), each of 360/15 = 24 degrees.
We know that the sum of the exterior angles of a regular polygon is 360°. Since the exterior angle is 24°, then 24°n = 360° divide both sides by 24°; n = 15 Thus a 15-sided regular polygon has an exterior angle of 24°. If you don't remember the above fact, you can work in this way: If the exterior angle is 24°, then the angle of polygon will be 156° (180 - 24). Since the sum of the angle of the polygon is equal to (n - 2)180°, then we have: 156° n = (n - 2)180° 156° n = 180°n - 360° subtract 156°n and add 360° to both sides; 360° = 24°n divide by 24° to both sides; 15 = n
384
360 / 24 = 15.Since 24 is a factor of 360, and also obviously a factor of itself,it must be the greatest common factor of 24 and 360.
Divide the angle sector by 360 and multiply it by 24 square meters. The area is equal to 3 square meters.
The LCM is 360.
multiply or divide by 360 degree
24 x 15 = 360
0.0417
The LCM is 360.