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Q: Divisibility pattern for 7

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If a number is divisible by 5 and 7, it's divisible by 35.

Double the last digit and subtract the last digit from the remaining digits.

The divisibility rule for 42 isdivisibility by 2, ANDdivisibility by 3, ANDdivisibility by 7.Divisibility by 2 requires the number to be even. That means it must end in 0, 2, 4, 6 or 8.Divisibility by 3 requires that the digital root of the number is divisible by 3. That is, the sum of the digits is divisible by 3. If the first sum is large, you can calculate the digital root of the digital root (and again, if necessary) and check that for divisibility by 3.The divisibility rule for 7 is more difficult.Take the last digit (units).From the number formed by the remaining digit, subtract twice the last digit.If the answer is divisible by 7 (including zero or negative numbers), then the original number is divisible by 7.For large numbers, repeat the process to bring the number down to a manageable size.

There is no easy rule for divisibility by 34.

no it does not and the smallest missing factor that would allow for divisibility is 13

Related questions

It is somebody talking about divisibility.

2,3,9,6

7 is only divisible by 1 and itself.

The number must be divisible by 2 and by 7.

Yes. 210 is evenly divisible by seven.

2 x 7 x 7 = 98

If the last digit doubled subtracted from the rest is a multiple of 7, the whole number is divisible by 7.

It is: 7

All Factors of 91:1, 7, 13, 91

Double the last digit. Subtract it from the rest. If the result is divisible by 7, the original number is divisible by 7.

If a number is divisible by 5 and 7, it's divisible by 35.

For any practical purpose, it is easier to simply divide, instead of looking for fancy divisibility rules. However, you can apply the divisibility rules for 3 and for 7. This works because (a) their product is 21, and (b) these numbers are relatively prime.

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