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Q: Divisiblity of 4

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No rule

if the number is divisible by 2 and 3 then it is divisible by 6 =D

4 +4+4+4+4+4+4+4+4=40

(4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4) ÷ 4 = 27

1 = 44 / 44 2 = 4 * 4 / (4 + 4) 3 = (4 + 4 + 4) / 4 4 = 4 + (4 * (4 - 4)) 5 = (4 + (4 * 4)) / 4 6 = 4 + ((4 + 4) / 4) 7 = (44 / 4) - 4 8 = 4 + 4 + 4 - 4 9 = 4 + 4 + (4 / 4) 10 = (44 - 4) / 4 11 = (4 / 4) + (4 / .4) 12 = (4 + 44) / 4 13 = 4 + ((4 - .4) / .4) 14 = (4 * (4 - .4)) - .4 15 = 4 + (44 / 4) 16 = (44 - 4) * .4 17 = (4 * 4) + (4 / 4) 18 = (44 * .4) + .4 19 = (4 + 4 - .4) / .4 20 = 4 * (4 + (4 / 4))

Related questions

No rule

No - because it's an odd number !

To find out if a number is divisible by 8 the number must be divisible by 2 and 4!

60.

-9

If the sum of the digits is a multiple of 3, yhen the number is divisible by 3.

if the number is divisible by 2 and 3 then it is divisible by 6 =D

Yes,because we know the divisiblity test of 2 that is last no. should be odd.

Add the digits together and if the result is divisible by 9, the original number is divisible by 9.

The rule to decide if a number is divisible by 9 is to look at the sum of the digits. If the sum of the digits is divisible by 9, then so is the number.

Just carry out the division, and see if you get an integer. It isn't worth the trouble to memorize or, worse, figure out divisibility rules for all sorts of large numbers.

A number is divisible by 15 if it is divisible by 5, and by 3. For example, 165 is divisible by 15, since it ends in 5, and the sum of its digits is divisible by 3.

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