No - 54/7 = 7.714285 recurring (that is, 7.714285714285..)
54 divided by 7 is 7.71
1,2,3,4,6,9,13,18,26,54.
54 ÷ 7 = 7 5/7
Well, honey, let me break it down for you. The numbers that go into 35 are 1, 5, 7, and 35. As for 54, you've got 1, 2, 3, 6, 9, 18, 27, and 54. So there you have it, the divisors of 35 and 54 laid out for ya.
7.7143
54 divided by 7 is 7.71
378 ÷ 7 = 54
54 x 7 = 378 miles
1,2,3,4,6,9,13,18,26,54.
54 ÷ 7 = 7 5/7
0.1296
Well, honey, let me break it down for you. The numbers that go into 35 are 1, 5, 7, and 35. As for 54, you've got 1, 2, 3, 6, 9, 18, 27, and 54. So there you have it, the divisors of 35 and 54 laid out for ya.
Seven times... with a remainder of 5.
To find the answer with a remainder of 54 when divided by 7, first divide 54 by 7. The quotient is 7 (since 7 times 7 is 49) and the remainder is 54 - 49 = 5. Thus, 54 divided by 7 gives a quotient of 7 with a remainder of 5, not 54. If you meant a number that has a remainder of 54 when divided by 7, you would need to find a number like 54 + 7k, where k is an integer.
7.7143
7% of 54 = 3.78
(35+54+7+64+54+38)/6 = 42