Many say YES, but only using a parlor trick called "limits"... limits arbitrarily stop a repeating number (using theorems (just theory)) so it no longer repeats infinitely.
Take 0.333... (repeating)... by definition, it's an infinite repetition of the number 9 behind the decimal point, and will never be a finite number without the use of "limits" to stop the repetition (rounding the number to the nearest and stopping).
Think of these numbers as distances, and it becomes easier to understand... 1/3, as an expression distance, is a finite point (by definition) on a line representing a distance between two points, however, 0.333 repeating cannot be a point on a line because the 3 repeats to infinity... adding another "3" to the repeating number never gets you 1/3rd of the way to the next number... remember that adding another "3" to the infinite series is only adding "0.3" and is NOT the same as adding "0.333 repeating". So adding 0.3 infinitely will never get you to a "finite" point... kinda the "point" to the concept of infinity.
"Infinity" melts mathematicians brains, so they had to invent theories incorporating "limits" to keep them from burning out their little brain cells.
I have no problem admitting that for all "practical" purposes, 0.999... might as well be equal to 1, however, the reality is that on the scale of "the infinite", .999 repeating, by definition, is infinitely far from ever being 1 :o)
9 repeating = infinity. If you mean 0.9999... repeating as a fraction, that is equal to 1. Proof: 1/3 = 0.3 repeating (0.3333...) 2/3 = 0.6 repeating (0.6666...) 1/3 + 2/3 = 3/3 = 1 0.3333... + 0.6666... = 0.9999... 0.9999... = 1 End of Proof:
The last part of your question contains the mistake here. .9 repeating is, in fact, equal to one according to essentially all professional mathematicians. There are tons of proofs on this topic, but I'll give a couple more basic ones since this doesn't seem to be intended as a necessarily rigorous question. By definition: Real numbers must simply have a number (or really infinite numbers) between them. There is no number between .9 repeating and 1. By definition: Two real numbers are the same if they subtract to equal 0. 1-.9 repeating is .000(infinite repeating zeroes)001. That number is provably smaller than any positive quantity and is obviously not negative. Not positive and not negative means 0, and thus 1 and .9 repeating are the same. By Algebra: 1/9 = .1 repeating. 9 * 1/9 = 9 * .1 repeating. 9/9 = .9 repeating = 1. This must be true because we always modified each side of the equation in the same way, and the algebra is therefore sound. In conclusion, 9/9 = 1 = 1/9 + 8/9 = .9 repeating. Further proofs and background: http://en.wikipedia.org/wiki/0.999...
It is equal to 43/9.
1/9
0.9 recurring is equal to 1. While this seems illogical, this can be proven by saying that, if 0.3 recurring is equal to 1/3, then 1/3 x 3 = 0.9 recurring, or 1.
0.999... repeating = 1. That may sound strange, but it is true!
9 repeating = infinity. If you mean 0.9999... repeating as a fraction, that is equal to 1. Proof: 1/3 = 0.3 repeating (0.3333...) 2/3 = 0.6 repeating (0.6666...) 1/3 + 2/3 = 3/3 = 1 0.3333... + 0.6666... = 0.9999... 0.9999... = 1 End of Proof:
The last part of your question contains the mistake here. .9 repeating is, in fact, equal to one according to essentially all professional mathematicians. There are tons of proofs on this topic, but I'll give a couple more basic ones since this doesn't seem to be intended as a necessarily rigorous question. By definition: Real numbers must simply have a number (or really infinite numbers) between them. There is no number between .9 repeating and 1. By definition: Two real numbers are the same if they subtract to equal 0. 1-.9 repeating is .000(infinite repeating zeroes)001. That number is provably smaller than any positive quantity and is obviously not negative. Not positive and not negative means 0, and thus 1 and .9 repeating are the same. By Algebra: 1/9 = .1 repeating. 9 * 1/9 = 9 * .1 repeating. 9/9 = .9 repeating = 1. This must be true because we always modified each side of the equation in the same way, and the algebra is therefore sound. In conclusion, 9/9 = 1 = 1/9 + 8/9 = .9 repeating. Further proofs and background: http://en.wikipedia.org/wiki/0.999...
It is equal to 43/9.
8/9 = 0.88888 (repeating) equal to 88.888 (repeating) percent
No but if there's a decimal in front of the first 9 and you round it in the nearest tenth it will be.
5/9 or 0.55555(repeating) or 55.555555(repeating)%
It is 4/9.
It is 0.499... (with the 9 repeating).
6/9 = 0.6666 repeating
0.11 repeating can be written as the fraction 1/9.
In fraction form, 53.3 repeating can be expressed as 533/9. To convert a decimal with a repeating decimal point to a fraction, we first determine the non-repeating part of the decimal (in this case, 53), then subtract it from the entire decimal to isolate the repeating part (0.3 repeating). Next, we express the repeating part as a fraction over 9 (since there is one digit repeating). Thus, 53.3 repeating is equal to 533/9 in fraction form.