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Since the square root of 13 is an irrational number, sqrt(13)/625 will also be an irrational number.

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It is non terminating.

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This is really good

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awsum, thx

Q: Does square root of 13 divided by 625 have a terminating decimal or a non-terminating decimal?

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No, it is not.

Neither; it is a non-repeating, non-terminating decimal - it is an irrational value.

Yes.

45 is not a perfect square number. the closest perfect squares are 49 and 36. But it is the square of the irrational number 6.708204... (an infinite, non-terminating, non-repeating decimal).

Irrational numbers are pi(3.14...), a non-terminating decimal with no pattern(ex.-0.3456789...), and non-perfect squares(ex.-square root of 34).

Related questions

Nonterminating Decimal: A decimal that continues without end.For example:The square root of 2 = 1.414213562… Therefore, the square root of 2 is a nonterminating decimal.

A non-terminating decimal.

No, it is not.

Neither; it is a non-repeating, non-terminating decimal - it is an irrational value.

No, it is neither.

No, it is neither.

The square root of 325, 18.027756377319946465596106337352…, is an irrational number because its decimal expansion is nonterminating and nonperiodic.

Neither because the square root of 400 is 20

Square root of 2...

None of the items in the list.

Yes, the square root of 7 is an irrational number. Written in decimal form, it never terminates or repeats. âˆš7 is approximately 2.645751311064591

Yes.