No. Variance and standard deviation are dependent on, but calculated irrespective of the data. You do, of course, have to have some variation, otherwise, the variance and standard deviation will be zero.
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The answer will depend on the underlying distribution for the variable. You may not simply assume that the distribution is normal.
z =0 and P(X< x) = 0.5 Explanation: z = (x-xbar)/sd, where xbar is the estimated mean or average of the sample, sd is the standard deviation, and x is the value of the particular outcome. We change x to z so that we can use the normal distribution or t-tables tables, which are based on a zero mean and 1 standard deviation. For example: What is the probability that the mean value of the distribution is 5 or less, given the sample average is 5 and the sd is 2? The z-score would be (5-5)/2 which is equal to 0. The probability, if we assume the normal or t-distribution, is 0.50. (see normal distribution tables) I hope this makes sense to you. The normal distribution is symmetrical. Per the example, a sample average of 5 tells you there is equal chance of the population mean being above and below 5.
Assume that you are correlating two variables x and y. If there is an increasing relationship between x and y, (that is , the graph of y=a+bx, slopes upward), the correlation coefficient is positive. Similarly, if there is a decreasing relationship, the correlation coefficient is negative. The correlation coefficient can assume values only between -1 and 1.
I assume you refer to the distance between the points.I assume you refer to the distance between the points.I assume you refer to the distance between the points.I assume you refer to the distance between the points.
The answer is 9^4 (9 to the 4th power.) OR Standard form may also refer to factoring, in which case it is (9x9)(9x9); which, through FOIL (First, Inner, Outer, Last), would still give you the simplified answer of 9^4. Standard form in Algebra, or graphing, is much different and involves moving all variables to one side and all constants to the other...but you don't have variables so I'm going to assume you aren't asking for that kind of standard form.