If you mean: y = 12x+1 then it has a positive slope of 12 and a y intercept of 1
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It would be the negative of the negative reciprocal. And since the negative of a negative is a posivie, it is the positive reciprocal.. For example, if the slope was -3, the other would be 1/3.
If a line has a slope m then a line perpendicular to it has a slope -1/m ( negative inverse). For example if a line has slope positive 2, its perpendicular has slope -1/2
The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.
The slope is always positive A negative slope will always pass through quadrant II and IV
A perpendicular lines slope is always the negative or opposite reciprocal of a lines slope. Therefore, if your slope is -13/1 then the perpendicularity of the other line is 1/13. The 13 would change positive there fore its its already a negative number then change it posiive.