Let's represent the number of marbles in each bag as x and the number of bags as 2x. Since each bag contains the same number of marbles, the total number of marbles can be expressed as x * 2x = 32. This simplifies to 2x^2 = 32. Solving for x, we find x = √(32/2) = √16 = 4. Therefore, there are 4 marbles in each bag.
12
There is no possible solution since "you" would have to have a negative number at the start.
There are at least 11 green marbles in the bag.
Well, honey, if the pattern starts with 5 marbles, and each line has a number that's four less than twice the previous line, the sixth line would have 9 marbles. So, you better have 9 marbles lined up and ready to go if you want to keep this pattern going.
33
12
He has a number of yellow marbles that leaves a reminder of 2 when divided by 3 and is a number smaller than 22. That is the number of yellow marbles = 2(mod 3).
There is no possible solution since "you" would have to have a negative number at the start.
There must be 67 marbles.
668
There are at least 11 green marbles in the bag.
22 marbles are in the fifth line.
33 marbles must be in the sixth line
The fifth line will have 19 marbles. 4 5 7 11 19
17
36
Well, honey, if the pattern starts with 5 marbles, and each line has a number that's four less than twice the previous line, the sixth line would have 9 marbles. So, you better have 9 marbles lined up and ready to go if you want to keep this pattern going.