64 m2 perimeter_of_square = 4 x side_length ⇒ side_length = perimeter_of_square ÷ 4 area_of_square = side_length2 Thus if perimeter is 32 m: side_length = 32 m ÷ 4 = 8 m ⇒ area = (8 m)2 = 64 m2
it could men m times m, which would be 2m or m2. It would usually be 2m. ↑ that would only work for m² not 2m. 2m in that sense is 2*m not m*m. now m2 is usually associated with slope 2. m1=slope1 m2=slope2, but the numbers are usually subscripts.
(1.7 m)2 = 2.89 m2 1.7 m2 is a measure of area, for example a rectangle 1 m by 1.7 m or 85 cm by 2 m
(1.6002 m)2 = 2.56064004 m2 ≈ 2.5606 m2
(m - 2)(m - 10)
35 * * * * * How about 3.2*10 = 32 m2 instead?
64 m2 perimeter_of_square = 4 x side_length ⇒ side_length = perimeter_of_square ÷ 4 area_of_square = side_length2 Thus if perimeter is 32 m: side_length = 32 m ÷ 4 = 8 m ⇒ area = (8 m)2 = 64 m2
(15/m) - m + 8 = 1015/m - m = 215 - m2 - 2m = 0 or m2 +2m - 15 = 0This factoises as (m +5)( m - 3), so m = 3 or -5
m2+m-90 = (m-9)(m+10) when factored
-m2+3m-2 -m2+2m+m-2 -m(m -2)+1(m-2) (-m+1)(m-2) or
The numbers are 8 and 32 and the max product is 256.Let one number be mLet the other be nWe have m + 4n = 64So 4n = 64 - mor n = 16- m/4We want mn = m(16 - m/4) to be a max value.That is to say the product of these two numbers equals -(1/4)m2 + 16m.Now depending on you level of math there are many ways to do this.If you know calculus, you can take the derivative of f(m)= -(1/4)m2 + 16mand you find it as -(1/2)m + 16.Now you would set that equal to zero which will indicates m = 32.So you have:-(1/2)m + 16 = 0m = 32To find the other number, substitute 32 for m into the equation n = 16 - m/4 and solve for n.So that the other number is 16-32/4 or 8.Thus, the numbers are 8 and 32, and their product is 256.Since f(m)=16m-m2 /4, we can also look at f(32)= 16(32)-322 /4=512-256=256METHOD TWONow if you don't know calculus, here is another way to do it.You can see that f(m)= -(1/4)m2 + 16m is a quadratic function written in standard form asax2 + bx + c, where a = -1/4, b = 16, and c = 0.The graph is a parabola which opens down since the sign of the coefficient of m2 is negative (a = -1). We need to find the vertex of the parabola where the y-coordinate will be the max value.The formula for the vertex is (-b/2a, f(-b/2a)), so we have-b/2a = -16/(2(-1/4)) = 32, andf(m) = -(1/4)m2 + 16mf(-b/2a) = f(32) = -(1/4)(32)2 + 16(32) = 256Therefore, the vertex of the parabola is at (32, 256) and the maximum value of 256 happens when m = 32. Since this max value is the product of m and n, then n = 8 (256/32).METHOD THREEOnce again look at the function f(m)=16m-m2 /4 and write it in standard formf(m)=-m2 /4 +16mNow complete write this as -1/4(m2 -64m) and complete the square.We havef(m)=-1/4(m -32)2 +256This tells us the graph is a parabola with vertex (32, 256)Since the parabola opens downward, 256 is the max.
Area of half a circle in square m = pi*radius2 divided by 2
3.82 m x 3.70 m = (3.82 x 3.70) m2 = 14.134 m2
Multiply m by m.
m2-7m-30 = (m+3)(m-10) when factored
if by m2 you mean m multiplied by 2, then m= 2 2/3if by m2 you mean m squared, then m still =2 2/3, because the m squared becomes m times m which equals 2m
I'm assuming you meant m2-n2+196 m2-n2=-196 m2=-196+n2 m=14i+n n=m-14i