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Eugenia had five times as many quarters as dimes. If the total value of her coins was $16.20 how many of each kind of coin did she have?
Let x= the amount of dimes Eugenia had (dimes are worth 10)
Let 5x= the amount of quarters Eugenia had (quarters are worth 25)
Equation: 10(x) + 25(5x)=1620 (because that is how many cents there are)
10(x)+25(5x)=1620
10x+125x=1620
135x=1620
1/135(135)=1/135(1620)
1x= 12
x=12
check
10(x) + 25(5x)=1620
10(12)+25(5x12)=1620
120+25(60)=1620
120+1500=1620
1620=1620
x=12
5x=1500
Therefore Eugenia had 12 dimes and 60 quarters
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