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Eugenia had five times as many quarters as dimes. If the total value of her coins was $16.20 how many of each kind of coin did she have?

Let x= the amount of dimes Eugenia had (dimes are worth 10)

Let 5x= the amount of quarters Eugenia had (quarters are worth 25)

Equation: 10(x) + 25(5x)=1620 (because that is how many cents there are)

10(x)+25(5x)=1620

10x+125x=1620

135x=1620

1/135(135)=1/135(1620)

1x= 12

x=12

check

10(x) + 25(5x)=1620

10(12)+25(5x12)=1620

120+25(60)=1620

120+1500=1620

1620=1620

x=12

5x=1500

Therefore Eugenia had 12 dimes and 60 quarters

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