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How do you express 27.25 percent as a ratio?
27.25 percent is the same as 0.2725, which is also the same as 2725/10000. Reduced to lowest terms, that is 109/400.
Is 100 kcal equal to 100 cal?
No.
What is 109 divisible by?
1 & 109
How loud is 109 decibels?
109 decibles
What is Half of 109?
It is: 109/2 = 54.5
How is the energy value of food measure?
Joules (J) or kilocalories (cal) (kcal in Europe)
How many kilocalories of heat does the operation of a 1200-W hair dryer produce each second?
1 W = 1 J/s 4190 J = 1 kcal 1200 J/s * 1 kcal/4190 J =0.286 kcal/s =17 kcal/min. Aren't you glad you don't have to run that hair dryer by pedaling a bicycle?
How many kcal?
1 kcal = 1000 cal. 1 cal = 4.18 J
What are the energy formulas involving specific heat mass and temperature change?
E = mass x sp ht x Δ°t (Finding Energy)where E (Energy) or Q (Quantity of Heat), mass (g), sp ht (aka specific heat, J/g°C*[typical] or cal/g°C or kcal/g°C), and Δ°t (temperature change). Finding Temperature ChangeDivide energy by mass multiplied by specific heat. Δ°t = Energy-- Mass * sp htIn order to find the final temperature (if problem is asking for this), add or subtract the original temperature and the new temperature together.Tf = original temperature +/- new temperatureIf energy is added, the temperatures will be added together; if energy is removed, the temperatures will be subtracted.Finding MassDivide energy by specific heat multiplied by temperature change. Mass = Energy------- sp ht * Δ°tFinding Specific HeatDivide energy by mass multiplied by temperature change. Sp ht = Energy------- Mass * Δ°tConverting Form of Energy (joules, kcal, and cal)Sometimes a problem will have E be shown in cal/g°C or kcal/g°C but will be asking for Joules or even vice versa. This means a conversion has to take place. Cal --> Joules and Joules --> cal-Calories (Cal) --> Joules (J)Multiply # cal by 4.184 Joules (J).Conversion Factor# cal x 4.184 J = Joules---------- 1 cal1 cal = 4.184 Joules-Joules (J) --> Calories (Cal)Divide # Joules (J) by 4.184Conversion Factor# J x 1 cal = cal--- 4.184 J1 Joule = 0.239005736 calKcal --> Joules (J) and Joules (J) --> Kcal-Joules --> kcal (Joules --> cal --> kcal)Divide # J by # kcal multiplied by 103Conversion Factor# Joules x 1 cal - * - 1kcal = kcal---------- 4.184J -- 103 cal1 kcal = 4,184 Joules 1 Joule = 0.000239005736 kcal-Kcal --> Joules (J) (Kcal --> cal --> Joules)Multiply # kcal by 103 cal by 4.184JConversion Factor# kcal * 103 cal * 4.184J = Joules (J)----------- 1 kcal --- 1 calAnother relationship that is good to understand: 1 kcal = 1000 (103) cal 1 cal = 0.001 (10-3) kcal
How do you express in a scientific notation 1000000000?
It is: 1.0*109
What is the Specific heat of lead in Joules?
· 1 J/(kg K) = 2.389x10-4 kcal/(kg oC) = 2.389x10-4 Btu/(lbm oF) · 1 kJ/(kg K) = 0.2389 kcal/(kg oC) = 0.2389 Btu/(lbm oF) · 1 Btu/(lbm oF) = 4,186.8 J/ (kg K) = 1 kcal/(kg oC) · 1 kcal/(kg oC) = 4,186.8 J/ (kg K) = 1 Btu/(lbm oF) Metal Specific Heat Capacity - cp (kJ/kg K)(kcal/kgoC) (Btu/lbmoF) Lead 0.13 0.031 0.03 · 1 J/(kg K) = 2.389x10-4 kcal/(kg oC) = 2.389x10-4 Btu/(lbm oF) · 1 kJ/(kg K) = 0.2389 kcal/(kg oC) = 0.2389 Btu/(lbm oF) · 1 Btu/(lbm oF) = 4,186.8 J/ (kg K) = 1 kcal/(kg oC) · 1 kcal/(kg oC) = 4,186.8 J/ (kg K) = 1 Btu/(lbm oF) Metal Specific Heat Capacity - cp (kJ/kg K)(kcal/kgoC) (Btu/lbmoF) Lead 0.13 0.031 0.03
Convert 6.5kcal to Joules?
1 cal ~ 4.18 J <-- known 6.5 kcal = 6500 cal = 4.18 [J / cal] * 6500 [cal] = 27170 [J] or 2.72e+4 [J]
What is another way to express 1230000000 in mathematical terms?
1.23 x 109
When 100 g of gasoline undergoes combustion 9560 kJ of energy are released Express the heat released 9560 kJ in kilocalories?
1 kJ is approximately 0.239 kcal9560 kJ * (0.239 kcal/kJ) = 2284.84 kcal
How do you express 1224 million numerically?
1,244,000,000 or 1.244 x 109 or to keep it 1224 million you can express it as: 1224 x 106
What represents the greatest amount of energy 1000 cal 500 Cal 100 kcal or 100000 J?
Tek a dump
What is faraday constant?
•96485 coulomb/mol of electrons (for J) •23054 C/mol (for Cal) •23.054 C/mol (for kCal) •
