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What else can I help you with?
How do you express 27.25 percent as a ratio?
27.25 percent is the same as 0.2725, which is also the same as 2725/10000. Reduced to lowest terms, that is 109/400.
Is 100 kcal equal to 100 cal?
No.
What is 109 divisible by?
1 & 109
How loud is 109 decibels?
109 decibles
What is the greatest common factor of 327 and 109?
109
How many joules are there in 7.72 kcal?
To convert kilocalories (kcal) to joules (J), you can use the conversion factor: 1 kcal = 4,184 J. Therefore, to find the number of joules in 7.72 kcal, you multiply 7.72 by 4,184. This calculation gives you approximately 32,253.68 J. So, 7.72 kcal is equivalent to about 32,254 joules.
How is the energy value of food measure?
Joules (J) or kilocalories (cal) (kcal in Europe)
What represents the greatest amount of energy 1000 cal 500 Cal 100 kcal or 100000 J?
100000 J represents the greatest amount of energy compared to 1000 cal, 500 Cal, and 100 kcal. 1 Cal = 1000 cal = 1 kcal = 4184 J. Therefore, 100000 J is equivalent to about 23.9 kcal.
How many kcal?
1 kcal = 1000 cal. 1 cal = 4.18 J
Is 3.25 kcal the same amount of energy as 3.25 J?
No, those are different units. Both are units of energy, however. The recommended unit is the joule, or multiples such as kJ, etc. - that's the international unit for energy.
What are the energy formulas involving specific heat mass and temperature change?
E = mass x sp ht x Δ°t (Finding Energy)where E (Energy) or Q (Quantity of Heat), mass (g), sp ht (aka specific heat, J/g°C*[typical] or cal/g°C or kcal/g°C), and Δ°t (temperature change). Finding Temperature ChangeDivide energy by mass multiplied by specific heat. Δ°t = Energy-- Mass * sp htIn order to find the final temperature (if problem is asking for this), add or subtract the original temperature and the new temperature together.Tf = original temperature +/- new temperatureIf energy is added, the temperatures will be added together; if energy is removed, the temperatures will be subtracted.Finding MassDivide energy by specific heat multiplied by temperature change. Mass = Energy------- sp ht * Δ°tFinding Specific HeatDivide energy by mass multiplied by temperature change. Sp ht = Energy------- Mass * Δ°tConverting Form of Energy (joules, kcal, and cal)Sometimes a problem will have E be shown in cal/g°C or kcal/g°C but will be asking for Joules or even vice versa. This means a conversion has to take place. Cal --> Joules and Joules --> cal-Calories (Cal) --> Joules (J)Multiply # cal by 4.184 Joules (J).Conversion Factor# cal x 4.184 J = Joules---------- 1 cal1 cal = 4.184 Joules-Joules (J) --> Calories (Cal)Divide # Joules (J) by 4.184Conversion Factor# J x 1 cal = cal--- 4.184 J1 Joule = 0.239005736 calKcal --> Joules (J) and Joules (J) --> Kcal-Joules --> kcal (Joules --> cal --> kcal)Divide # J by # kcal multiplied by 103Conversion Factor# Joules x 1 cal - * - 1kcal = kcal---------- 4.184J -- 103 cal1 kcal = 4,184 Joules 1 Joule = 0.000239005736 kcal-Kcal --> Joules (J) (Kcal --> cal --> Joules)Multiply # kcal by 103 cal by 4.184JConversion Factor# kcal * 103 cal * 4.184J = Joules (J)----------- 1 kcal --- 1 calAnother relationship that is good to understand: 1 kcal = 1000 (103) cal 1 cal = 0.001 (10-3) kcal
How many kilocalories of heat does the operation of a 1200-W hair dryer produce each second?
The heat produced by a 1200-W hair dryer can be converted to kilocalories by multiplying the power in watts by the conversion factor of 0.001 kcal/s per watt. Therefore, 1200 W hair dryer would produce 1.2 kilocalories of heat each second.
What is the Specific heat of lead in Joules?
· 1 J/(kg K) = 2.389x10-4 kcal/(kg oC) = 2.389x10-4 Btu/(lbm oF) · 1 kJ/(kg K) = 0.2389 kcal/(kg oC) = 0.2389 Btu/(lbm oF) · 1 Btu/(lbm oF) = 4,186.8 J/ (kg K) = 1 kcal/(kg oC) · 1 kcal/(kg oC) = 4,186.8 J/ (kg K) = 1 Btu/(lbm oF) Metal Specific Heat Capacity - cp (kJ/kg K)(kcal/kgoC) (Btu/lbmoF) Lead 0.13 0.031 0.03 · 1 J/(kg K) = 2.389x10-4 kcal/(kg oC) = 2.389x10-4 Btu/(lbm oF) · 1 kJ/(kg K) = 0.2389 kcal/(kg oC) = 0.2389 Btu/(lbm oF) · 1 Btu/(lbm oF) = 4,186.8 J/ (kg K) = 1 kcal/(kg oC) · 1 kcal/(kg oC) = 4,186.8 J/ (kg K) = 1 Btu/(lbm oF) Metal Specific Heat Capacity - cp (kJ/kg K)(kcal/kgoC) (Btu/lbmoF) Lead 0.13 0.031 0.03
How do you express in a scientific notation 1000000000?
It is: 1.0*109
When 100 g of gasoline undergoes combustion 9560 kJ of energy are released Express the heat released 9560 kJ in kilocalories?
1 kJ is approximately 0.239 kcal9560 kJ * (0.239 kcal/kJ) = 2284.84 kcal
Convert 6.5kcal to Joules?
1 cal ~ 4.18 J <-- known 6.5 kcal = 6500 cal = 4.18 [J / cal] * 6500 [cal] = 27170 [J] or 2.72e+4 [J]
How do you calculate kcal in chemistry?
To calculate kilocalories (kcal) in chemistry, you can use the formula: Energy (kcal) mass (g) x specific heat capacity (J/gC) x change in temperature (C). This formula helps determine the amount of energy required to raise the temperature of a substance.
