150 = 2 x 3 x 52
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the prime factorization of 150= 2x3x52 If we use all the factors, the answer would of course be 150 if we use just 2,3 and a single 5, not 52 , then the answer is 30
2 x 3 x 5^2
The Highest Common Factor (HCF) of 45, 60, and 150 is the largest number that divides all three numbers without leaving a remainder. To find the HCF, we first need to find the prime factors of each number. The prime factors of 45 are 3 x 3 x 5, the prime factors of 60 are 2 x 2 x 3 x 5, and the prime factors of 150 are 2 x 3 x 5 x 5. The common prime factors among the three numbers are 3 and 5. Therefore, the HCF of 45, 60, and 150 is 3 x 5, which equals 15.
There are five whole numbers between 1 and 150 that have exactly 3 different factors. Whole numbers between 1 and 150 with exactly 3 different factors must be the square numbers whose square roots are prime.To find the complete list begin counting... skip 1, not prime; 2 is prime and 2 squared is 4; 3 is prime and 3 squared is 9; skip 4 b/c it is not prime; 5 is prime and 5 squared is 25; 6 not prime; 7 prime and 7 squared is 49; 8 not prime; 10 not prime; 11 prime and squared is 121; 12 is not prime; 13 prime, but squared it is greater than 150. The complete list is 4, 9, 25, 49, and 121. 4 has 1, 2, 4 9 has 1, 3, 9 25 has 1, 5, 25 49 has 1, 7, 49 121 has 1, 11, 121
150 multiplied by 180 is 27,000.