0
Let's take a moment to appreciate the beauty of this mathematical expression. To factor m^2 + 9m + 20, we need to find two numbers that multiply to 20 and add up to 9. Those numbers are 4 and 5. So, the factored form is (m + 4)(m + 5). Just like painting a happy little tree, sometimes all it takes is a little patience and observation to reveal the true beauty within.
Still curious? Ask our experts.
Chat with our AI personalities
Steve
Coach
Lao
Add your answer:
Earn +20 pts
How do you factor m2 -9m 8?
(m - 8)(m - 1)
What is the area of a rectangle 9m x 5m?
9m x 5m = 45 m2
How do you factor m2-12m 20?
(m - 2)(m - 10)
How do you factor m2 - 9?
-7
How do you prove that n must divide m if n is square-free and n divides m squared?
Consider m, and its set of prime factors. e.g. m = 130 = 2 x 5 x 13 then m2 = (2 x 5 x 13)(2 x 5 x 13) n is a factor of m2. It must therefore be formed by the multiplication of a subset of the prime factors of m2. If this subset is contained in just one pair of brackets (see above) then it is contained in the prime factorisation of m, and so n is definitely a factor of m. [For instance, 2 x 5 = 10 is a factor of 1302 and 130. (2 x 5 x 13)(2 x 5 x 13)] If this subset spans both pairs of brackets, then n is a factor of m2 but not of m. If this is the case, however, n contains a repeated factor, and is not 'square-free'. [For instance, 2 x 2 x 5 = 20 is a factor of 1302 but not 130. (2 x 5 x 13)(2 x 5 x 13).But being divisible by 4, it is not square free.] To summarise: for a number to be divisible by m2 but not by m, it is necessarythat it has a repeated prime factor. For n to divide m, it is therefore sufficient (but not necessary) that n divides m2 and is square free.
