6
2x + 6 = 2(x + 3) so 2x + 6 = 0 implies x = -3 Now, substitute x = -3 in 8x3 + 20x2 + 36 which is -8*27 + 20*9 + 36 = -216 + 180 + 36 = 0 So -3 is a root of 8x3 + 20x2 + 36 ie, by the remainder theorem, (x + 3) is a factor. Also, each of the coeffivcients in the expression is even, so 2 is also a factor. So 2*(x + 3) or (2x + 6) is a factor.
2x2 + 7x + 6 = 2x2 + 4x + 3x + 6 = 2x(x + 2) + 3(x + 2) = (x + 2)(2x + 3)
2x3+2x2-12x take out GCF - 2x 2x(x2+x-6) factor - find factors of -6 that add up to 1 2x(x-2)(x+3)
The given expression is x + 6 = 2x + 5. Subtract both sides by x to get: x - x + 6 = 2x - x + 5 6 = x + 5 Subtract both sides by 5 to get: 6 - 5 = x + 5 - 5 x = 1
(x - 2)(2x - 3)
30+12x = 6(5+2x)
It is (x+6)(x-4) when factored
2x+5x+6 7x+6 But this expression is simplified, not factored. In order to factor something out of this expression, you must find a common term between 7x and 6. Only one term has a variable, but both terms have a constant. So, for instance, you could factor out a six: 6 ( 7x/6 + 1 ).
2x + 6 = 2(x+3)
It is an expression that can be simplified to 5y+2x-6
You would factor 2x2 + 7x + 6 into (2x + 3) (x+2)
X = 6 5x + 2x = 42
2x+12=2(x+6)
The expression simplifies to 5x + 6.
2(2x + 3)
x2 - 2x - 24 = (x - 6)(x + 4)