2(x+3)
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2x + 6 = 2(x + 3) so 2x + 6 = 0 implies x = -3 Now, substitute x = -3 in 8x3 + 20x2 + 36 which is -8*27 + 20*9 + 36 = -216 + 180 + 36 = 0 So -3 is a root of 8x3 + 20x2 + 36 ie, by the remainder theorem, (x + 3) is a factor. Also, each of the coeffivcients in the expression is even, so 2 is also a factor. So 2*(x + 3) or (2x + 6) is a factor.
2x2 + 7x + 6 = 2x2 + 4x + 3x + 6 = 2x(x + 2) + 3(x + 2) = (x + 2)(2x + 3)
2x3+2x2-12x take out GCF - 2x 2x(x2+x-6) factor - find factors of -6 that add up to 1 2x(x-2)(x+3)
The given expression is x + 6 = 2x + 5. Subtract both sides by x to get: x - x + 6 = 2x - x + 5 6 = x + 5 Subtract both sides by 5 to get: 6 - 5 = x + 5 - 5 x = 1