Find an equation of variation where y varies directly as x. One pair of values is y = 80 when x = 40
If P varies directly with q, r and s then P = kqrs, where k is a constant. As 70 = k x 7 x 5 x 4 = 140k : k = 70/140 = 1/2 The equation of joint variation is P = ½qrs.
When two variables are related in such a way that the ratio of their values always remains the same, the two variables are said to be in direct variation. y=2x is direct variation y=x+2 is not direct variation
Any variation is very sensitive to extreme values!
zeros values at which an equation equals zero are called roots,solutions, or simply zeros. an x-intercept occurs when y=o ex.) y=x squared - 4 0=(x-2)(x+2) (-infinity,-2)(-2,2) (2,infinity)
that would be limited to 3 and -3 for values of x
If P varies directly with q, r and s then P = kqrs, where k is a constant. As 70 = k x 7 x 5 x 4 = 140k : k = 70/140 = 1/2 The equation of joint variation is P = ½qrs.
For a direct variation equation the constant MUST be 0. Then the ratio of a pair of values of the two variables is the slope.
It is, in fact, an identity - which is an equation which is true for all values of the variable.
They are called the solutions or roots of the equations.
When two variables are related in such a way that the ratio of their values always remains the same, the two variables are said to be in direct variation. y=2x is direct variation y=x+2 is not direct variation
-4
If y and x are related inversely, then the equation for y can be said to be:y = k/xTo find the constant k, substitute 12 for y and 6 for x (a pair of values that are known to satisfy the equation).y = k/x12 = k/612 X 6 = k72 = kThe value of the variation constant k is 72.
Since ( y ) varies directly as ( x ), we can express this relationship as ( y = kx ), where ( k ) is the constant of variation. Given that ( y = 15 ) when ( x = 5 ), we can find ( k ) by substituting these values: ( 15 = k(5) ), leading to ( k = 3 ). Thus, the equation is ( y = 3x ). Now, to find ( y ) when ( x = 19 ), we substitute ( 19 ) into the equation: ( y = 3(19) = 57 ).
There are no exclude values of the equation, as given.
10.
It is a quadratic equation and the values of x are: -1/2 and 6
Any variation is very sensitive to extreme values!