This is my method to find GCD of 2 big numbers A and B and expressing that gcd of the form mA + nB
First, let us find the gcd. Let us call it as d
1) Divide the bigger number by the smaller one.
2) Divide the smaller number by the remainder u get in step 1.
3) Divide the step 1 remainder by step 2, then each remainder by the next remainder and so on.
4) Reach the step when u get no remainder at all. The divisor will be the LCM.
Let me explain it with an example.
Q. Find the gcd of 858 and 325 and express it in the form of m858 + n325.
Solution :
858 = 325*2 + 208
325 = 208*1 + 117
208 = 117*1 + 91
117 = 91*1 + 26
91 = 26*3 + 13
26 = 13.2
thr4, gcd 0f 858 and 325 is d = 13
d = 13 = 91 - 26*3
= 91 -3(117 - 91*1)
= 91*4 - 117*3
=4(208-117) - 117*3
= 4*208 - 7*117
= 4*208 - 7(325-208)
=11*208 -7*325
=11*(858-325*2) - 7*325
=11*858 - 29*325
thr4, d = 13 = m*858 + n*325 where m =11 and n = -29
236 + 89 = 325
Half of 650 is 325. To find half of a number, you simply divide it by 2. In this case, 650 divided by 2 equals 325. So, half of 650 is 325.
To find the value of the unknown number, you would divide 325 by 5. This gives you the value of the unknown number, which is 65. Therefore, 5 times 65 equals 325.
Oh, dude, you want me to do math now? Fine, fine. So, 325 divided by 8 is 40.625, but if you want to know what times 8 equals 325, it's 40.625 times 8, which is 325. There you have it, math wizardry at its finest.
15% of 325= 15% * 325= 0.15 * 325= 48.75
To find what plus what equals 325, we can set up an equation as x + y = 325. Since both x and y are unknowns, there are multiple possible combinations that could satisfy this equation. Some examples include 200 + 125 = 325, 150 + 175 = 325, or even decimal values like 162.5 + 162.5 = 325.
200 + 325 = 525
325 + 345 = 670
325 + 50 = 375
600 + 325 = 925
They both add up to 325
325
325 + 634 - 547 = 412
597
471
236 + 89 = 325
300 + 25 = 325