This is my method to find GCD of 2 big numbers A and B and expressing that gcd of the form mA + nB
First, let us find the gcd. Let us call it as d
1) Divide the bigger number by the smaller one.
2) Divide the smaller number by the remainder u get in step 1.
3) Divide the step 1 remainder by step 2, then each remainder by the next remainder and so on.
4) Reach the step when u get no remainder at all. The divisor will be the LCM.
Let me explain it with an example.
Q. Find the gcd of 858 and 325 and express it in the form of m858 + n325.
Solution :
858 = 325*2 + 208
325 = 208*1 + 117
208 = 117*1 + 91
117 = 91*1 + 26
91 = 26*3 + 13
26 = 13.2
thr4, gcd 0f 858 and 325 is d = 13
d = 13 = 91 - 26*3
= 91 -3(117 - 91*1)
= 91*4 - 117*3
=4(208-117) - 117*3
= 4*208 - 7*117
= 4*208 - 7(325-208)
=11*208 -7*325
=11*(858-325*2) - 7*325
=11*858 - 29*325
thr4, d = 13 = m*858 + n*325 where m =11 and n = -29
236 + 89 = 325
15% of 325= 15% * 325= 0.15 * 325= 48.75
75% of $325= 75% * 325= 0.75 * 325= $243.75
To find averages, you add all the numbers given and divide by the numbers given. (325 + 332 + 345) / 3 = 334. Your answer is 334.
25% of 1300 = 1300*25/100 = 325
200 + 325 = 525
325 + 345 = 670
600 + 325 = 925
325 + 50 = 375
They both add up to 325
325
325 + 634 - 547 = 412
597
471
236 + 89 = 325
300 + 25 = 325
15 + 310 = 325