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Q: Find s when t equals 10 if s is inversely proportional to t and s equals 100 when t equals 5?

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y varies inversely as x2 so y = c/x2 for some constant c. When x = 5, y = 4 So c = x2y = 100 that is y = 100/x2 Then, when x = 2, y = 100/4 = 25

x = 20

100+20+1

In order to find the correct answer simply do the following calculation 100 - 54 = 46

Percentage error = 100*error/standard = 100*(3.98-3.14)/3.14 = 100*0.84/3.14 = 84/3.14 = 26.75%

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Yes. The gravitational force is inversely proportional to the square of the distance; meaning, for example, that if you increase the distance by a factor of 10, the force will be reduced by a factor 100.Yes. The gravitational force is inversely proportional to the square of the distance; meaning, for example, that if you increase the distance by a factor of 10, the force will be reduced by a factor 100.Yes. The gravitational force is inversely proportional to the square of the distance; meaning, for example, that if you increase the distance by a factor of 10, the force will be reduced by a factor 100.Yes. The gravitational force is inversely proportional to the square of the distance; meaning, for example, that if you increase the distance by a factor of 10, the force will be reduced by a factor 100.

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At a greater distance, the gravitational force is less. More specifically, the gravitational force is inversely proportional to the square of the distance. For example, if the distance is increased by a factor 10, the force decreases by a factor of 102 = 100.At a greater distance, the gravitational force is less. More specifically, the gravitational force is inversely proportional to the square of the distance. For example, if the distance is increased by a factor 10, the force decreases by a factor of 102 = 100.At a greater distance, the gravitational force is less. More specifically, the gravitational force is inversely proportional to the square of the distance. For example, if the distance is increased by a factor 10, the force decreases by a factor of 102 = 100.At a greater distance, the gravitational force is less. More specifically, the gravitational force is inversely proportional to the square of the distance. For example, if the distance is increased by a factor 10, the force decreases by a factor of 102 = 100.

The relationship between friction and the efficiency of a machine is when friction increases, efficiency decreases, and vice versa. That is why you can never have 100% efficiency, because there is always at least a little friction. They are inversely proportional, meaning, higher friction equals less efficiency.

That is the universal law of gravitation. The force of gravity is proportional to the product of the masses, and inversely proportional to the square of the distance (that is, at 10 times the distance, the force will be reduced to 1/100 of the original value).

y varies inversely as x2 so y = c/x2 for some constant c. When x = 5, y = 4 So c = x2y = 100 that is y = 100/x2 Then, when x = 2, y = 100/4 = 25

The gravitational force is inversely proportional to the square of the distance. For example, at 10 times the distance, the force will decrease by a factor of 102 = 100.

30

x = 20

Divide the percentage by 100 and that is the value.

100+20+1

Given x=k1y and x=k2/z x=125 ,y=5 then k1=25 x=125 , z=4 then k2=125(4)=500 If y=4 ,z=5 then x=25y = 100

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