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If you mean: x^2+y^2+8x-10y+5 = 0

Completing the squares: (x+4)^2+(y-5)^2 -16-25+5 = 0

So: (x+4)^2+(y-5)^2 = 36

Therefore center of circle is at (-4, 5) with a radius of 6

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Q: Find the center and radius of the circle with this equation x 2 plus y 2 plus 8x-10y plus 5 0?
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