38.5
Sum of squares? Product?
They are the squares of the numbers 1 to 31. Use a calculator to find them.
Oh, what a happy little question! The product of the first 30 counting numbers is a big number, but we can handle it. It's called the factorial of 30, which is written as 30! and equals 265252859812191058636308480000000. Just imagine all the beautiful possibilities that number holds!
12 and 12, whose squares will be 144 each. If either of the numbers is smaller than 12, then the other will be larger than 12 and its square will be larger than 144.
What I would do is square each of the consecutive even numbers, and then add their squares. It depends on how complex you want the answer to be. If you need a formula to do it, then use the following. If it's always starting at two, then use the formula: Sum of even numbers' squares from 0 to w. x=w/2 f(x) = (4*x^3+6*x^2+2*x)/3 If you put in 1, then you get the first even number squared. If you put in two, then you get the sum of the squares of the first two even numbers. Three will give you the sum of the squares of the first three even numbers. If you need to vary where it starts (e.g. adding the squares of the even numbers from 8 to 26) the use that formula with the larger number (13, because 26 is the thirteenth even number) and then subtract the formula at the lower number minus one (3, since 8 is the fourth even number, and 4-1=3). F(13)=3276; F(3)=56; 3276-56=3220. So, the sum of the squares of the even numbers from 8 to 26 is 3220. Sum of even numbers' squares from w to z. x=(w/2)-1 y=z/2 f(y)-f(x)
First, find the least common multiple (LCM). Then, multiply that number by successive counting numbers.
Divide 60 by the first six counting numbers.
To get a list of the squares of the first 1000 numbers we can do:> [n^2 | n sum [n^2 | n
Sum of squares? Product?
you find the length and width by counting the numbers on the side to find the width and counting the numbers going across to find the length
count the number of squares, then times by the area of each square A=1/2(base*height) can also be used
You will not find one "a" until you get to one thousand.
The whole numbers include the counting numbers, plus zero.
Multiply them by successive counting numbers.
They are the squares of the numbers 1 to 31. Use a calculator to find them.
you can find it by counting how many numbers they are in the equation
thinking