Very simple, let's mount a linear system: x=measure of the angle; y=supplement; z=complement: I:x+y= 180; II:x+z= 90; III: y+z= 150; Summing I with II we have: I+II: 2x+y+z= 270; III: y+z=150 Now, subtracting III from I+II we have a simple equation: 2x=120; >x= 60< So, the angle whose sum of the measures of its complements and supplement is 150, has 60 degrees.
An angle of 108 degrees does not have a complement because is greater than 90 degrees. Its supplement angle has a measure of 180 - 108 = 72 degrees.
Angle=54oComplement: 90-54=36oSupplement: 180-54=126o
Complement . . . another angle, of 53 degrees Supplement . . . another angle, of 143 degrees
26 degrees
60 degrees
To find the degree measure of the supplement of the complement of a 42-degree angle, first calculate the complement: 90 degrees - 42 degrees = 48 degrees. Next, find the supplement of that result: 180 degrees - 48 degrees = 132 degrees. Therefore, the degree measure of the supplement of the complement of a 42-degree angle is 132 degrees.
33
An angle of 108 degrees does not have a complement because is greater than 90 degrees. Its supplement angle has a measure of 180 - 108 = 72 degrees.
Angle=54oComplement: 90-54=36oSupplement: 180-54=126o
Complement . . . another angle, of 53 degrees Supplement . . . another angle, of 143 degrees
(180°-x) + (90°-x) = 240°270° - 2x = 240°30° = 2x15° = xThe measure of the angle is 15°.The supplement is 165°, the complement is 75°, and their sum is 240°.
19 degrees and 109 degrees respectively
26 degrees
60 degrees
74 degrees
The measure of an angle whose complement is four ninths its supplement?æ is 18 degrees. It is calculated as follows: let y be the angle, its complement will be (90-y) degrees and its supplement will be (180-y)?æ degrees and?æ since it complement is?æ 4/9 its supplement; then?æ it is?æ?æ(90-y)= 4/9(180-y).?æ Hence, you will get 18 degrees when you solve the equation.
The difference between 90 degrees and an angle is its complement. 90 - 62 = 28 degrees.