In euclidean (plane) geometry, the sum of the interior angles of any triangle is 180 degrees. Add the two angles you know (right angles = 90 degrees) and subtract that sum from 180.
Without more information on the problem, that's the most I can assume
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To find the measure of the third angle of a triangle, you can use the fact that the sum of all three angles in a triangle is always 180 degrees. So, if one angle measures 50 degrees and the other measures 85 degrees, you can subtract their sum from 180 to find the measure of the third angle. Therefore, the third angle would measure 180 - 50 - 85 = 45 degrees.
If that's a triangle, the third angle is 90 degrees.
Assuming the third angle is x... 180 = 15 +85 + x 180 = 100 +x 80 = x The third angle is 80 degrees
Use a protractor.
Let the measure of the first angle be x⁰. So that the second angle would be (x + 21)⁰, and the third one would be (x - 15)⁰.Since the sum of angle measures in a triangle is 180⁰ we have:x + x + 21 + x - 15 = 1803x = 174x = 58Thus, the first angle is 58⁰, the second angle is 79⁰, and the third angle is 43⁰.