1=13-0
7=23-1
25=33-2
61=43-3
121=53-4
so the next number must be 63-5=216-5=211
In general the nth term, an =n3-(n-1)
49, 36, 25...
Find by using the differences of the differences of the numbers.
121: ± 11625: ± 25
289 because each consecutive prime number is squared.
There appears to be no discernible pattern for these numbers, other than them increasing in arbitrary multiples of 6.
yes
121.
169
225
fraction 121-25 written in a decimal = 4.84121/25:= 121 ÷ 25= 4.84 in decimal
49, 36, 25...
121 is 25 percent of 484.
The given sequence appears to follow a pattern related to cubic numbers. Specifically, the terms can be represented as ( n^3 - n ) for ( n = 1, 2, 3, 4, 5 ). Thus, the next term for ( n = 6 ) would be ( 6^3 - 6 = 216 - 6 = 210 ). Therefore, the next term in the sequence is 210.
The nth term is 7n-3 and so the next term will be 39
Find by using the differences of the differences of the numbers.
121: ± 11625: ± 25
289 because each consecutive prime number is squared.