8 collinear points determine 28 unique line segments
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6*5/2 = 15.
a polygon.
If one vector is a multiple of the other vector than they are collinear).Let n equal any natural number (1, 2, 3, 4, ...) and vequal a vector with both amagnitudeand a direction.vn = nv (e.g., v3 = 3v)Vn will always be collinear to v, because it is just a multiple of v (the multiple being n)To verify if two vectors are collinear, if you can factor out a multiple, to return to theoriginalvector, than they are collinear.
There are an infinite number of any kind of points in any plane. But once you have three ( 3 ) non-collinear points, you know exactly which plane they're in, because there's no other plane that contains the same three non-collinear points.
The points are collinear, and there is an infinite number of planes that contain a given line. A plane containing the line can be rotated about the line by any number of degrees to form an unlimited number of other planes.If, on the other hand, the points are not collinear, then the plane has no wriggle room: it is stuck fast in one place - there can be only one plane containing all the points. Provided they are non-colinear, three points will define a plane.