8 collinear points determine 28 unique line segments
6*5/2 = 15.
a polygon.
If one vector is a multiple of the other vector than they are collinear).Let n equal any natural number (1, 2, 3, 4, ...) and vequal a vector with both amagnitudeand a direction.vn = nv (e.g., v3 = 3v)Vn will always be collinear to v, because it is just a multiple of v (the multiple being n)To verify if two vectors are collinear, if you can factor out a multiple, to return to theoriginalvector, than they are collinear.
There are an infinite number of any kind of points in any plane. But once you have three ( 3 ) non-collinear points, you know exactly which plane they're in, because there's no other plane that contains the same three non-collinear points.
The points are collinear, and there is an infinite number of planes that contain a given line. A plane containing the line can be rotated about the line by any number of degrees to form an unlimited number of other planes.If, on the other hand, the points are not collinear, then the plane has no wriggle room: it is stuck fast in one place - there can be only one plane containing all the points. Provided they are non-colinear, three points will define a plane.
For ( n ) collinear points, the number of line segments that can be formed is given by the combination formula ( \binom{n}{2} ), which represents the number of ways to choose 2 points from ( n ) points. This simplifies to ( \frac{n(n-1)}{2} ). Therefore, the total number of segments formed by ( n ) collinear points is ( \frac{n(n-1)}{2} ).
The number of non-overlapping segments formed by ( n ) collinear points is given by the formula ( \frac{n(n-1)}{2} ). This is because each pair of points can form a unique segment, and the total number of pairs of ( n ) points is calculated using combinations: ( \binom{n}{2} ). Thus, for ( n ) points, the maximum number of non-overlapping segments is ( \frac{n(n-1)}{2} ).
6*5/2 = 15.
If there are n points then the maximum number of lines possible is n*(n-1)/2 and that maximum is attained of no three points are collinear.
If the points are collinear, the number of possible planes is infinite. If the points are not collinear, the number of possible planes is ' 1 '.
From 8 non-collinear points, any two points can be connected to form a straight line. The number of lines that can be formed is given by the combination formula ( \binom{n}{2} ), where ( n ) is the number of points. For 8 points, this is calculated as ( \binom{8}{2} = \frac{8 \times 7}{2} = 28 ). Therefore, 28 straight lines can be formed from 8 non-collinear points.
a polygon.
You can have an infinite number of planes passing through three collinear points.
Only one if they are non-collinear. An infinite number if they are collinear.
Collinear means in the same straight line. And since a line consists of an infinite number of points, collinear has an infinite number of points - not just 3. n the other hand, while any two points must be collinear (they have to both be on the line that joins them), it is always possible to find a third point which is not collinear with the first two (Euclid).
A line segment defined by ( n ) points is divided into ( n + 1 ) segments. Each point creates a division between two segments, so with ( n ) points, there are ( n ) divisions. Therefore, the total number of segments formed is equal to the number of divisions plus one, resulting in ( n + 1 ) segments.
The answer depends on whether any of the points are collinear: that is, whether they lie on the same line. No matter how many points you have, if they are all collinear you will have only one ray.If you have N points, the maximum number of rays is attained when no three of them are collinear. This number is N*(N-1)/2.