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We are told: 16y2 = 120x - 225

The y-intercepts will happen where x equals zero, so we can say:

16y2 = 120(0) - 225

16y2 = -225

y2 = -225 / 16

y = √(-225 / 16)

y = ±15i/4

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Q: Find the y-intercepts of 16y squared equals 120x-225?
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