n2 - (n + 2) = 10
n2 - n - 2 = 10
n2 - n - 12 = 0
(n + 3)(n - 4) = 0
n = -3,4
Of these, only 4 fits the requirements of the problem. To check:
(4)2 - (4 + 2) = 10
16 - 6 = 10
So, the numbers are 4 and 6.
3 and 4
two consecutive integers of the square root of 66 found between
The two consecutive integers between which the square root of 75 lies are 8 and 9. 82 is 64 and 92 is 81.
Try it! Find the square of some integers, until you either (a) find one that gives exactly 360 when squared, or (b) find two consecutive integers, one of which is smaller, the other larger, than 360. You can also take your calculator and find the square root of 360. If it is an integer (no decimals), that means it is a square number.
between which two consecutive integers does the square root lie 123
3 and 4
4 and 6
two consecutive integers of the square root of 66 found between
The square roots of 117 are irrational numbers and so are not two integers - consecutive or otherwise.
The integers are 7, 8 and 9.
The product of four consecutive integers is always one less than a perfect square. The product of four consecutive integers starting with n will be one less than the square of n2 + 3n + 1
The square of 3 is 9, which does not lie between consecutive integers. Perhaps you mean the square root of 3, which lies between 1 and 2.
hi
The two consecutive integers between which the square root of 75 lies are 8 and 9. 82 is 64 and 92 is 81.
Try it! Find the square of some integers, until you either (a) find one that gives exactly 360 when squared, or (b) find two consecutive integers, one of which is smaller, the other larger, than 360. You can also take your calculator and find the square root of 360. If it is an integer (no decimals), that means it is a square number.
between which two consecutive integers does the square root lie 123
9 and 10