To find the answer you must derive an equation with one variable so, set x-y=100 thus y=100-x now substitute into your product equation
x(100-x) then differentiate with respect to x
d/dx= 100-2x
then set the equation equal to zero and solve for x
x= 50 and note that some may think the minimum is 0 but in fact 50*-50= -2500 which is far less than zero.
-76 and 76 whose product is -5776.
11
-5 * 5 = -25
you are a nerd
Suppose the smaller of the two numbers is x. Then the other number is x+22. Their product is x*(x+22) = x2 + 22x This has a minimum when 2x = -22 or x = -11. When x = 11, the two numbers are -11 and 11 with a product of -121.
-12
-76 and 76 whose product is -5776.
11
-5 * 5 = -25
you are a nerd
Suppose the smaller of the two numbers is x. Then the other number is x+22. Their product is x*(x+22) = x2 + 22x This has a minimum when 2x = -22 or x = -11. When x = 11, the two numbers are -11 and 11 with a product of -121.
Suppose the smaller of the two numbers is x. Then the larger is x + 16 and their product is x*(x+16) = x2 + 16x This has its minimum when 2x = -16 or x = -8 When x = -8, the two numbers are -8 and 8 and their product is -64.
The two numbers whose sum is 58 and whose difference is 16 are 21 and 37.
2 and 1 .their sum is 3 .difference is 1
31 and 20
31 and 18
53 and 22..