0
To find the answer you must derive an equation with one variable so, set x-y=100 thus y=100-x now substitute into your product equation
x(100-x) then differentiate with respect to x
d/dx= 100-2x
then set the equation equal to zero and solve for x
x= 50 and note that some may think the minimum is 0 but in fact 50*-50= -2500 which is far less than zero.
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Earn +20 ptsQ: Find two numbers whose difference is 100 and whose produce is a minimum?
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