50 * * * * * z = -0.67449 to z = +0.67449
I believe your question is to find a range going from the mean to a z-value on the standard normal distribution that corresponds to 17% of the area. A normal distribution goes from values of minus infinity to positive infinity. A standard normal distribution has a mean of 0 and an standard deviation of 1. It is usually best if you draw a diagram, in this case a bell shape curve with mean = 0. The area to the left of the mean is 50% of the total area. We find a z value that corresponds to 67% (50% + 17%) of the area to the left of this value. This can be done either with a lookup table or a spreadsheet program. I prefer excel, +norminv(0.67) = 0.44. The problem could also be worded to find the area going from a z-value to the mean. In this case, we must find a z-value that corrsponds to 33% (50-17). Using Excel, I calculate +norminv(0.33) = -0.44.
The Z value is 0.
z = 18.5 6z - 24 = 2z + 50 Take the -24 to the other side of the equals and change its sign; take the 2z to the other side of the equals and change its sign: => 6z - 2z = 50 + 24 => 4z = 74 Divide both sides by 4: => z = 18.5
Very simple, let's mount a linear system: x=measure of the angle; y=supplement; z=complement: I:x+y= 180; II:x+z= 90; III: y+z= 150; Summing I with II we have: I+II: 2x+y+z= 270; III: y+z=150 Now, subtracting III from I+II we have a simple equation: 2x=120; >x= 60< So, the angle whose sum of the measures of its complements and supplement is 150, has 60 degrees.
80=4x, z=6x. find Z. x=80/4, x=20. z=6x20 z=120 answer= 120
50 * * * * * z = -0.67449 to z = +0.67449
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X = 50 => Z = (50 - 70)/12 = -20/12 = -1.33 So prob(X < 50) = Prob(Z < -1.33...) = 0.091
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In Roman numerals L and C are 50 and 100 respectively. So substitute 50 and 100 into the equation and let the unknown be called z. 50-z = 100 -z = 100-50 -z = 50 --z = -50 Solution: z = -50 Substituting -50 into the equation: 50--50 = 100 or L--L = C. Remember that in maths a double minus sign before a number changes that number into a plus number. Check it out on your calculator. David Gambell, Merseyside, England.
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The possible values of z are (a cis b), where a is any number between and including 0 and 2 and b is any of 0, 60, 120, 180, 240 and 300 degrees. The minimum modulus of z - 2, that is |z - 2|, is 0.
Jay Z
Jay-Z
This level requires some trial and error math to find the code.You have to find C, D, Z, and N so that:C+D=Z*N and Z+N=C*D.Plug in some numbers and you'll find that C = 3, D = 2, Z = 1, and N = 5.See related links for screenshots.