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you forgot a few symbols (i.e. =,+) but what i think you are trying to say is f(n)=f(n-1)+f(n-2) which is the formula for the fibonnacci sequence
Fn = Fn-1 + Fn-2
Fn = Fn-1 + Fn-2 And F0 = F1 = 1
The first number, f1 = 1 The second number, f2 = 1 After that the sequence is defined recursively: fn = fn-1 + fn-2 for n=3, 4, 5, ...
Yes. For every measurable function, f there's a sequence of simple functions Fn that converge to f m-a.e (wich means for each e>0, there's X' such that Fn|x' -->f|x' and m(X\X')<e).
The Fibonacci sequence has this form: Fn + 2 = Fn + 1 + Fn with these starting values F0 = 0 and F1 = 1. Find the 7th term via similar computation by substituting the values in! You should get... F2 = F1 + F0 F2 = 1 + 0 F2 = 1 F3 = F2 + F1 F3 = 1 + 1 F3 = 2 F4 = 3 F5 = 5 F6 = 8 F7 = 13 So the 7th term of the Fibonacci sequence is 13.