I have just calculated it, i am quite sure about my calculation but dont be mad if i made some mistakes. :)
If "r1<r2" and the hight of the truncated cone "m" (distance between r1 and r2) then the distance "d" between r1 and the center of mass is:
m*[ (r23/(r23-r13)) - ( (r24-r14)/(4*(r2-r1)*(r23-r13)) ) ]
I did a test. in case its cylinder r1→r2
With limr2→r1 you get d=(1/2)*m which is correct.
Hope I could help :)
btw. shortly after I did an another test, in case it is a cone. By cone d=(3/4)*m. If r1=0 (then you get a cone) the formula gives you the same answer d=(3/4)*m.
Now I am 97,5% sure that the formula is ok :)
The formula for calculating development surface area of a truncated cone is Avr = π [s (R + r) + R^2 + r^2]. The solution is area (A) subscript r where r is the radius of the top of the truncated cone. In this formula R stands for the radius of the bottom of the cone and s represents the slant height of the cone.
The answer will depend on what information you have.
There is no circumference of a cone, but, we only do the circumference of the circle. the formula for the circle is pi times D. D= Diameter
This is how you do it: Area = C(pi)r + (pi)r2 Where: C = the side length of the cone r = radius of the base (pi)r2 = the base of the cone C(pi)r = outside of cone
Volume of a cone: 1/3*pi*radius^2 *height
The formula for calculating development surface area of a truncated cone is Avr = π [s (R + r) + R^2 + r^2]. The solution is area (A) subscript r where r is the radius of the top of the truncated cone. In this formula R stands for the radius of the bottom of the cone and s represents the slant height of the cone.
A hollow truncated cone is a geometric shape that is cone-shaped. The formula to calculate the volume is s^2=h^2 + (R-r)^2.
m= (pieD + pied)/2 x height x thickness x density(kg/m^3)
A truncated cone is basically a cone with it's tip cut off.
sqrt( (R-r)^2 + h^2)where:R = radius of larger endr = radius of smaller endh = height of truncated cone
V = (1/3*Pi*h) * (R12 + R22 + R1*R2) Where R1 and R2 are the radii of the bases, and h is equal to the height of the truncated cone.
The answer will depend on what information you have.
no
funny shape
Some examples of solids are cube, sphere, cylinder, cone, pyramid, prism, tetrahedron, dodecahedron, octahedron, icosahedron, torus, cuboid, rhombic dodecahedron, ellipsoid, oloid, trapezohedron, truncated cone, truncated cuboctahedron, truncated dodecahedron, truncated icosahedron.
a truncated cone
For a circular cone: sqrt( (R-r)^2 + h^2) where: R = radius of larger end r = radius of smaller end h = height of truncated cone For cones of other shapes the average of the area of the top and bottom surfaces times the height (perpendicular to the plane of the top/bottom)