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I have just calculated it, i am quite sure about my calculation but dont be mad if i made some mistakes. :)
If "r1<r2" and the hight of the truncated cone "m" (distance between r1 and r2) then the distance "d" between r1 and the center of mass is:
m*[ (r23/(r23-r13)) - ( (r24-r14)/(4*(r2-r1)*(r23-r13)) ) ]
I did a test. in case its cylinder r1→r2
With limr2→r1 you get d=(1/2)*m which is correct.
Hope I could help :)
btw. shortly after I did an another test, in case it is a cone. By cone d=(3/4)*m. If r1=0 (then you get a cone) the formula gives you the same answer d=(3/4)*m.
Now I am 97,5% sure that the formula is ok :)
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What is the formula for calculating development surface are of truncated cone?
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The answer will depend on what information you have.
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What is the volume formula of a right cone with base area b and height h?
Volume of a cone: 1/3*pi*radius^2 *height
