I have just calculated it, i am quite sure about my calculation but dont be mad if i made some mistakes. :)
If "r1<r2" and the hight of the truncated cone "m" (distance between r1 and r2) then the distance "d" between r1 and the center of mass is:
m*[ (r23/(r23-r13)) - ( (r24-r14)/(4*(r2-r1)*(r23-r13)) ) ]
I did a test. in case its cylinder r1→r2
With limr2→r1 you get d=(1/2)*m which is correct.
Hope I could help :)
btw. shortly after I did an another test, in case it is a cone. By cone d=(3/4)*m. If r1=0 (then you get a cone) the formula gives you the same answer d=(3/4)*m.
Now I am 97,5% sure that the formula is ok :)
The formula for calculating development surface area of a truncated cone is Avr = π [s (R + r) + R^2 + r^2]. The solution is area (A) subscript r where r is the radius of the top of the truncated cone. In this formula R stands for the radius of the bottom of the cone and s represents the slant height of the cone.
The answer will depend on what information you have.
There is no circumference of a cone, but, we only do the circumference of the circle. the formula for the circle is pi times D. D= Diameter
This is how you do it: Area = C(pi)r + (pi)r2 Where: C = the side length of the cone r = radius of the base (pi)r2 = the base of the cone C(pi)r = outside of cone
Volume of a cone: 1/3*pi*radius^2 *height
The formula for calculating development surface area of a truncated cone is Avr = π [s (R + r) + R^2 + r^2]. The solution is area (A) subscript r where r is the radius of the top of the truncated cone. In this formula R stands for the radius of the bottom of the cone and s represents the slant height of the cone.
A hollow truncated cone is a geometric shape that is cone-shaped. The formula to calculate the volume is s^2=h^2 + (R-r)^2.
m= (pieD + pied)/2 x height x thickness x density(kg/m^3)
A truncated cone is basically a cone with it's tip cut off.
sqrt( (R-r)^2 + h^2)where:R = radius of larger endr = radius of smaller endh = height of truncated cone
V = (1/3*Pi*h) * (R12 + R22 + R1*R2) Where R1 and R2 are the radii of the bases, and h is equal to the height of the truncated cone.
The answer will depend on what information you have.
no
funny shape
For a circular cone: sqrt( (R-r)^2 + h^2) where: R = radius of larger end r = radius of smaller end h = height of truncated cone For cones of other shapes the average of the area of the top and bottom surfaces times the height (perpendicular to the plane of the top/bottom)
a truncated cone
A traditional cone has two faces but in fact it is a truncated cone. It has no verticles although it does have a vertex.