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I have just calculated it, i am quite sure about my calculation but dont be mad if i made some mistakes. :)

If "r1<r2" and the hight of the truncated cone "m" (distance between r1 and r2) then the distance "d" between r1 and the center of mass is:

m*[ (r23/(r23-r13)) - ( (r24-r14)/(4*(r2-r1)*(r23-r13)) ) ]

I did a test. in case its cylinder r1→r2

With limr2→r1 you get d=(1/2)*m which is correct.

Hope I could help :)

btw. shortly after I did an another test, in case it is a cone. By cone d=(3/4)*m. If r1=0 (then you get a cone) the formula gives you the same answer d=(3/4)*m.

Now I am 97,5% sure that the formula is ok :)

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Q: Formula for calculating centre of mass of truncated cone?
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