Suppose the number is x.
The sum of the number and two is x+2
Four times the sum is 4(x+2)
The number times 8 is 8x
24 less than the number times 8 is 8x-24
4(x+2) = 8x-24
4x+8=8x-24 so 4x = 32 and x = 8
three less than four = 1 1< *number* > 4 times the sum of the number + 1 1 < *number* > 5 So all numbers that are greater than one but less than five. 2, 3, 4
14-4x6=
four times a number is 6 more than three times a second number while 8 times the first number is 22 less than 7 times the second number. find the 2 numbers
You cannot find the answer to this question, because you do not know what the number is. If you are looking for how this question looks like algebraically, however, then it is 4n-5.
4x - 5
14
2x - 4 = 6x -4 = 4x x = -1
101 and 26
three less than four = 1 1< *number* > 4 times the sum of the number + 1 1 < *number* > 5 So all numbers that are greater than one but less than five. 2, 3, 4
12 and 56
4n-5 (Which is four times a number minus 5)
14-4x6=
10x - 4
4n - 1
Writing down the equation with x as the number you are trying to find, we get 3x = 4x-1. Simplifying the equation, we find that x=1. So, the answer is 1.
6a-4
four times a number is 6 more than three times a second number while 8 times the first number is 22 less than 7 times the second number. find the 2 numbers