Since a is the root of both equations, a satisfies them:
a2 - 5a + k = 0
a2 - 6a + 3k = 0
The right hand side of both the equations are same. Therefore,
a2 - 5a + k = a2 - 6a + 3k
6a - 5a = 3k - k
a = 2k
k = (a/2)
Substituting k = a/2 in one of the equations,
a2 - 5a + (a/2) = 0
Solving, a=9/2
k=a/2=9/4
Thus 'a' = (9/2) and 'k' = (9/4).
An equation has an equals sign ( = ). Equations assert the absolute equality of two expressions.
3
(a) rearrange one of the equations so that x or y is alone on one side of the equals sign.
Plug your ordered pair into both of your equations to see if you get they work.
Without any equality signs the given terms can't be considered to be equations.
They are parallel.
Neither perpendicular nor parallel
If you already know that x = -3 and y = 5 what linear equations are you wanting to solve?
CPUs, when given mathematical equations, apply the laws of mathematics to those equations. The equation a = a is true by the reflexive property of equality.
An equation has an equals sign ( = ). Equations assert the absolute equality of two expressions.
3
It will be any of the equations that has the same slope of y = 5x+9 but with a different y intercept
The equations will have the same slope as y = 5x+9 but a different y intercept
It depends on what equations are given.
since a=5 you can put that into your equation of a+7=12 a=5 a+7=12 5+7=12 12=12 Correct So yes the given number is a solution to the given equation
There is only one equation that is given in the question and that equation is not a direct variation.
Equations are not linear when they are quadratic equations which are graphed in the form of a parabola