To find HCF & LCM of two or more numbers.
Divide by prime numbers.
We note in this case, 12, & 30 are both even numbers, so they will divide by '2'.
Hence
2)12
2)6
3)3 = 1
&
2)30
3)15
5)5 = 1
First reduce both numberx to '1'.
Second;ly, we note that '2' & '3' bo appear in each set of numbers.
Hence 2 x 3 = 6 is the HCF
Having made this multiplication we are left with a '2' in the twelve and a '5' in the thirty..
Hence 6(HCF) X 2 X 5 = 60 the LCM.
Done!!!!
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-h/3 -4 = 13 -h -12 = 39 -h = 39+12 -h = 51 h = -51
h
12-
There are thirty hundreds in 3000.
The formula to determine the cubic volume of a box is (L)ength x (W)idth x (Height). For this problem we will assign:L=30, W=48, H=6. I will assume these measurements are in inches since that makes the most sense. Using 12 inches = 1 foot, we have to convert our measurements to inches first. L= 30/12=2.5 W=48/12=4.0 H = 6/12=0.5 Volume of a box = LWH 2.5 x 4.0 x 0.5 = 5 ft^3 *Note* You could also do the above problem without converting to feet until the end. To do this you use the original numbers in inches than divide by 12^3 at the end. Ex: (30 x 48 x 6) / 12^3 = 5 ft^3