According to question,
let the width be x
therefore, the length becomes x+4
1/2 . 2(l+b) = 36
now put the value of x and y in place of width and length,we get
4+2x=36
2x=36-4
2x=32
x=16 width
lly,
for the value of y(lenth)
16+4
=20 length
40 feet
66' x 3.27'
If the perimeter is 84 feet and the length is twice the width, then the length will be 28 feet and the width will be 14 feet.
14 feet (14+14+28+28 = 84)
Width = 16 feet Length = 38 feet
And the question is ...
divide perimeter by 6.
40 feet
the length of a rectangular garden is 2 feet longer than 3 times it's width .if the perimeter of the garden is 100 feet find the width and length of the garden
14 cm
10 cm
66' x 3.27'
It is 60 feet.
If the perimeter is 84 feet and the length is twice the width, then the length will be 28 feet and the width will be 14 feet.
Only one way to find out: measure the width and the length of the garden, add them together and multiply by two which gives the perimeter of the rectangular garden.
14 feet (14+14+28+28 = 84)
The dimensions are 12 feet by 4 feet