How to caculated arr at front office
$arr=array(2,5,4,6,7,8,1); for($i=0;$i<count($arr);$i++) { for($j=$i;$j<count($arr);$j++) { if($arr[$i] > $arr[$j]) { $temp=$arr[$i]; $arr[$i]=$arr[$j]; $arr[$j]=$temp; } } }
I did this as an answre to some common js questions , the question wasWrite a function which will return you first two times 1, then 2, then 3, then 5 and so on (Fibonacci numbers). Don't use any global variables.var fibonacci = (function () {var arr = [0, 1];return function () {var num = arr[arr.length - 1],len = arr.length;arr.push(arr[len - 1] + arr[len - 2]);return num;};}());//testvar i;for (i = 0; i < 10; i++) {console.log(fibonacci());}//1,1,2,3,5,8,13,21,34,55
There are many ways you can make a flowchart that will print and display a name 10 times. One example, will make you work with array, but you would input arr[1] for Sunday and arr[7] for Saturday.
#include<stdio.h> #include<conio.h> void main() { int a[10],count_even=0,count_odd=0,neg=0,i; printf(" Enter the value in Array \n"); for(i=0;i<10;i++) scanf("%d", &a[i]); /* Calculating number of odd and even integer's */ for(i=0;i<10;i++) { if((a[i]%2 ==0)) count_even++; if((a[i]%2==1)) count_odd++; if(a[i]<0) neg++; } /* display the number of odd and even integer's */ printf(" Total number of even integer are %d\n ",count_even); printf("Total number of odd integer are %d\n", count_odd); printf(" Total negative integer are %d", neg); getch(); }
Density is calculated by dividing the mass and volume of an object.
If the calculated ARR is greater that the predetermined ARR then accept the project. otherwise reject the project
Average Room Revenue (ARR) is calculated by dividing the total room revenue by the number of rooms sold over a specific period. For example, if a hotel earned $50,000 in room revenue by selling 1,000 rooms, the ARR would be calculated as follows: ARR = Total Room Revenue / Rooms Sold = $50,000 / 1,000 = $50. This means the average revenue earned per room sold is $50.
$arr=array(2,5,4,6,7,8,1); for($i=0;$i<count($arr);$i++) { for($j=$i;$j<count($arr);$j++) { if($arr[$i] > $arr[$j]) { $temp=$arr[$i]; $arr[$i]=$arr[$j]; $arr[$j]=$temp; } } }
No arr refers to address of array &arr refers address of address of array but compiler treats arr and & arr, so even you place arr and & arr no error only warnings will be displayed.
Yes, 'ARR' and 'ARR' are the same for char20. Whatever it means.
for example:int arr[3];arr[0] = 1; /* ok */arr[1] = 2; /* ok */arr[2] = 0; /* ok */arr[3] = -1; /* wrong */arr[-1] = -3; /* wrong */
ways of getting 14 1,1,6,6 6 arrangements (1,6,1,6; 1,6,6,1; 1,1,6,6; 6,6,1,1; 6,1,6,1; 6,1,1,6) 1,2,5,6 24 arr. 1,3,4,6 24 arr. 1,3,5,5 12 arr. 1,4,4,5 12 arr. 2,2,4,6 12 arr. 2,2,5,5 6 arr. 2,3,3,6 12 arr. 2,3,4,5 24 arr. 2,4,4,4 4 arr. 3,3,3,5 4 arr. 3,3,4,4 6 arr. Total: 146 146*(1/6)4 = 0.1127... so slightly over 1/9
9, the elements are: arr[0], arr[1], ... arr[9]
ARR = Average Room Revenue
formula for arr- total room revenue ARR= ------------------------------ total occupied room
Implement these methods: public static int smallest(int[] arr) { int small = arr[0]; for(int i = 1; i < arr.size(); i++) if(arr[i] < small) small = arr[i]; return small; } public static int largest(int[] arr) { int large = arr[0]; for(int i = 1; i < arr.size(); i++) if(arr[i] > large) large = arr[i]; return large; }
# include<stdio.h> # include<conio.h> void main() { int arr[10]; int i,j,temp; clrscr(); for(i=0;i<10;i++) scanf("%d",&arr[i]); for(i=0;i<9;i++) { for(j=i+1;j<10;j++) { if(arr[i]<arr[j]) { temp=arr[i]; arr[i]=arr[j]; arr[j]=temp; } } } printf("\nSorted array elements :\n"); for(i=0;i<10;i++) printf("%d ",arr[i]) ; getch(); }