there is no cube roots in negative
The cube root of 0.064 is 0.4
0.07
3√0.125 = 0.5 (there is only 1 real cube root of 0.125).
The cube root of 1.728 is 1.2
there is no cube roots in negative
The cube root of 0.064 is 0.4
Any real number - positive or negative - has exactly one real cube root. Any real number (except zero) has three cubic roots in the complex numbers; but only one of them is real.
0.07
3√0.125 = 0.5 (there is only 1 real cube root of 0.125).
There are 3 cube roots of 27. There are 2 square roots of 27 ( or any real number ). There are 4 fourth roots of 27 and so on:)
no, -6 is the cube root of -216.
They are 0.5 : it is a triple root.
The cube root of 1.728 is 1.2
There are 3 cube roots and these are:the real root -1.2599and the complex roots 0.6300 - 1.0911i and its conjugate, 0.6300 + 1.0911i.
yes, you can find a real root to the cube root of any negative real number. There will also be two complex roots which satisfy it, as well.
The short answer is "Nothing". In the complex domain, the number of nth roots of any real number is n. Every non-negative real number has 2 square roots. Every real number has 3 cube roots. Every non-negative real number has 2 real square roots and 2 imaginary ones. and so on. So what?