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How do you solve the factoring different of two square?
X2 - Y2 = (X + Y)(X - Y)
How do you differentiate the square root of 9-x2?
7
Is y equals x2 a nonlinear equation?
If you mean y = x2, then yes, it is nonlinear.
What is y x2 -1?
(x+1)(x-1) ;)
How do you solve x squared minus x minus 12?
There are several ways to solve x2-x-12. The easiest way, if you have a graphing calculator, is to put y = x2-x-12 and y = 0 into the graph and then solve for the intercepts. A way to do it without a graphing calculator is by factoring. x2-x-12 factors into (x-4) and (x+3). Then set (x-4) and (x+3) each equal to zero and solve. (x-4)=0 becomes x=4. (x+3)=0 becomes -3. Therefore, the answers are -3 and 4.
Solve this differential eq D2ydx2 -Y X2?
dy/dx= 2x therefore d2ydx2= 2 as this is positive we can tell that it is the minimum value in a curve
How do you solve this equation for x - y equals x - x2?
You cannot, in general, solve one equation with two unknown variables. x - y = x - x2 Subtract x from both sides: - y = - x2 Change signs: y = x2 And that is as far as you can go.
How do you solve the factoring different of two square?
X2 - Y2 = (X + Y)(X - Y)
Solve the equation y' plus x2y equals x2?
(2x)ysquared
How do you solve this problem it just says solve x2 plus 3y equals 7 3x plus y2 equals 3?
x2 + 3y = 7 3x + y2 = 3 3y = x2 + 7 y2 = -3x + 3 y = x2/3 + 7/3 y = ± √(-3x + 3) If you draw the graphs of y = x2/3 + 7/3 and y = ± √(-3x + 3) in a graphing calculator, you will see that they don't intersect, so that the system of the given equations has not a solution.
What is the inverse of y x2?
Y = X2 Inverse. Y = 1/X2 ======
Convert x2 plus y2 equals 2x?
What do you want to convert it to? x2 + y2 = 2x If you want to solve for y: x2 + y2 = 2x ∴ y2 = 2x - x2 ∴ y = (2x - x2)1/2 If you want to solve for x: x2 + y2 = 2x ∴ x2 - 2x = -y2 ∴ x2 - 2x + 1 = 1 - y2 ∴ (x - 1)2 = 1 - y2 ∴ x - 1 = ±(1 - y2)1/2 ∴ x = 1 ± (1 - y2)1/2
Z2 equals x2 plus y2?
What are we solving here for, Z, X, or Y?If solve for Z then the answer would be z = x + yIf solve for X then the answer would be z = z - yIf solve for Y than the answer would y = z - xHope this help.
Explain how do you write an equation of a line in standard form when two points on the line are given?
Th e two points are X1,Y1 and X2, Y2 slope, m, is y2-y1 divided by x2-x1 then standard form is y = mx +b plug in y2 for y and x2 for x and solve b or plug in y1 for y and x1 for x and solve b
How do I solve X squared plus X squared equals?
x2 + x2 = 2x2. Don't be thrown by squares (or other powers). y + y = 2y. Just treat x2 like you treat y. But remember, you can only add together the same powers of x, you cannot add together x and x2 (or other powers of x).
How do you solve y equals -x2 plus 3?
Set y as zero; now you have -x2+3=0. Multiply equation by -1; now you have x2-3=0. Add both sides by 3; now you have x2=3. Take the square root of both sides, and finally you have the answer, which is x=±√3.
If xy equals x2 plus y2 plus 2xy?
If:xy = x2 + y2 + 2xyThen:x2 + xy + y2 = 0Do you want to solve it for x?x2 + xy + (y/2)2 = (y/2)2 - y2(x + y/2)2 = y2/4 - y2x + y/2 = ± √(-3y2/4)x = -y/2 ± y√(-3) / 2x = (-y ± yi√3) / 2
